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german
3 years ago
13

The type of graph used to show how a part of something relates to the whole is which of the following?

Physics
2 answers:
nikitadnepr [17]3 years ago
7 0

<u>Question:</u>

The type of graph used to show how a part of something relates to the whole is which of the following? a. circle graph b. bar graph c. line graph d. direct proportion

<u>Answer:</u>

The type of graph used to show how a part of something relates to the whole is circle graph.

<u>Explanation:</u>

Circle graph also denoted as pie chart. It is generally used to show data analyzed in a small group. The circle graph is made in different parts based on the difference in the properties of the sample. It generally shows the relative analysis of each property for a given set of samples.

So, each parts in the circle graph will tell us the percentage of a property among the other properties present in the sample. Like we can say, if in a class of 100 students, 25 students are girls and 75 students are boys can be drawn in circle graph with two parts having smaller area for girl students and bigger area parts for boy students.

Slav-nsk [51]3 years ago
4 0

Answer:

Circle or pie graph is used to show how a part of something relates to the whole.

Explanation:

Pie graphs are easy to read and can present a very clear picture of the relationships.

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Two of the types of infrared light, ir-c and ir-a, are both components of sunlight. their wavelengths range from 3000 to 1,000,0
NikAS [45]
The energy of a light wave is calculated using the formula
E = hc/λ
h is the Planck's constant
c is the speed of light
λ is the wavelength
For the ir-c, the range is
<span>6.63 x 10^-34 (3x10^8) / 3000 = 6.63 x 10 ^-29 J
</span>6.63 x 10^-34 (3x10^8) / 1000000 = 1.99 x 10^-31 J

For the ir-a, the range is
6.63 x 10^-34 (3x10^8) / 700 = 2.84 x 10^-28 J
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6 0
3 years ago
Read 2 more answers
A 90 kg ice skater moving at 12.0 m/s on the ice encounters a region of roughed up ice with a coefficient of kinetic friction of
balandron [24]

Answer:

The skater covers a distance of <u>15 m</u> before stopping.

Explanation:

Let the distance traveled before stopping be 'd' m.

Given:

Mass of the skater (m) = 90 kg

Initial velocity of the skater (u) = 12.0 m/s

Final velocity of the skater (v) = 0 m/s (Stops finally)

Coefficient of kinetic friction (μ) = 0.490

Acceleration due to gravity (g) = 9.8 m/s²

Now, we know that, from work-energy theorem, the work done by the net force on a body is equal to the change in its kinetic energy.

Here, the net force acting on the skater is only frictional force which acts in the direction opposite to motion.

Frictional force is given as:

f=\mu N

Where, 'N' is the normal force acting on the skater. As there is no vertical motion, N=mg

∴ f=\mu mg=0.490\times 90\times 9.8=432.18\ N

Now, work done by friction is a negative work as friction and displacement are in opposite direction and is given as:

W=-fd=-432.18d

Now, change in kinetic energy is given as:

\Delta K=\frac{1}{2}m(v^2-u^2)\\\\\Delta K=\frac{1}{2}\times 90(0-12^2)\\\\\Delta K=45\times (-144)=-6480\ J

Therefore, from work-energy theorem,

W=\Delta K\\\\-432.18d=6480\\\\d=\frac{6480}{432.18}\\\\d=14.99\approx 15\ m

Hence, the skater covers a distance of 15 m before stopping.

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A 15-turn circular wire loop with a radius of 3.0 cm is initially in a uniform magnetic field with a strength of 0.5 T. The fiel
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Answer:

Explanation:

A )

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= 2 m /s

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time to cover distance of 50 m in lane 1

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