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german
3 years ago
13

The type of graph used to show how a part of something relates to the whole is which of the following?

Physics
2 answers:
nikitadnepr [17]3 years ago
7 0

<u>Question:</u>

The type of graph used to show how a part of something relates to the whole is which of the following? a. circle graph b. bar graph c. line graph d. direct proportion

<u>Answer:</u>

The type of graph used to show how a part of something relates to the whole is circle graph.

<u>Explanation:</u>

Circle graph also denoted as pie chart. It is generally used to show data analyzed in a small group. The circle graph is made in different parts based on the difference in the properties of the sample. It generally shows the relative analysis of each property for a given set of samples.

So, each parts in the circle graph will tell us the percentage of a property among the other properties present in the sample. Like we can say, if in a class of 100 students, 25 students are girls and 75 students are boys can be drawn in circle graph with two parts having smaller area for girl students and bigger area parts for boy students.

Slav-nsk [51]3 years ago
4 0

Answer:

Circle or pie graph is used to show how a part of something relates to the whole.

Explanation:

Pie graphs are easy to read and can present a very clear picture of the relationships.

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Light is shining in the images. Which object reflects a lot of light, absorbs a little light, and transmits almost no light?
SVEN [57.7K]
I believe it is B, the object that reflects a lot of light, absorbs a little light, and transmit almost no light.
6 0
3 years ago
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A displacement is related to time as x = A sin(2?ft), where A and f are constants. Find the dimensions of A. [Hint: A trigonomet
Luba_88 [7]

Answer:

The right option is C. i.e L

Explanation:

Dimension of a quantity is the collection of the indexes of each of the fundamental quantities contained in it.

Therefore, to get the dimension of A in the equation

X=Asin(2(pi)ft)

Making A the subject of the formula

A = X / (sin(2(pi)ft)

Since sin(2(pi)ft which is a trigonometric function does not have a dimension

A = L

The dimension of A is L

5 0
3 years ago
Electrolysis can be used to split up ionic compounds into their constituent<br> Science
tankabanditka [31]

Answer:

Electrolysis is the process by which ionic substances are decomposed (broken down) into simpler substances when an electric current is passed through them. ... Electricity is the flow of electrons or ions. For electrolysis to work, the compound must contain ions.

4 0
3 years ago
A 26.0 g ball is fired horizontally with initial speed v0 toward a 110 g ball that is hanging motionless from a 1.10 m -long str
mart [117]

Answer:

7.3 ms^{-1}

Explanation:

Consider the motion of the ball attached to string.

In triangle ABD

Cos50 = \frac{AB}{AD} \\Cos50 = \frac{AB}{L}\\AB = L Cos50

height gained by the ball is given as

h = BC = AC - AD \\h = L - L Cos50\\h = 1.10 - 1.10 Cos50\\h = 0.393 m

M  = mass of the ball attached to string = 110 g

V = speed of the ball attached to string just after collision

Using conservation of energy

Potential energy gained = Kinetic energy lost

Mgh = (0.5) M V^{2} \\V = sqrt(2gh)\\V = sqrt(2(9.8)(0.393))\\V = 2.8 ms^{-1}

Consider the collision between the two balls

m  = mass of the ball fired = 26 g

v_{o} = initial velocity of ball fired before collision = ?

v_{f} = final velocity of ball fired after collision = ?

using conservation of momentum

m v_{o} = MV + m v_{f}\\26 v_{o} = (110)(2.8) + 26 v_{f}\\v_{f} = v_{o} - 11.85

Using conservation of kinetic energy

m v_{o}^{2} = MV^{2} + m v_{f}^{2} \\26 v_{o}^{2} = 110 (2.8)^{2} + 26 (v_{o} - 11.85)^{2} \\v_{o} = 7.3 ms^{-1}

3 0
3 years ago
A light beam travels at 1.94×108 in quartz. The wavelength of the light in quartz is 355 .Part AWhat is the index of refraction
Alja [10]

A) 1.55

The speed of light in a medium is given by:

v=\frac{c}{n}

where

c=3\cdot 10^8 m/s is the speed of light in a vacuum

n is the refractive index of the material

In this problem, the speed of light in quartz is

v=1.94\cdot 10^8 m/s

So we can re-arrange the previous formula to find n, the index of refraction of quartz:

n=\frac{c}{v}=\frac{3\cdot 10^8 m/s}{1.94\cdot 10^8 m/s}=1.55

B) 550.3 nm

The relationship between the wavelength of the light in air and in quartz is

\lambda=\frac{\lambda_0}{n}

where

\lambda is the wavelenght in quartz

\lambda_0 is the wavelength in air

n is the refractive index

For the light in this problem, we have

\lambda=355 nm\\n=1.55

Therefore, we can re-arrange the equation to find \lambda_0, the wavelength in air:

\lambda_0 = n\lambda=(1.55)(355 nm)=550.3 nm

4 0
4 years ago
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