Answer:
p = 6.64 cm
Explanation:
For this exercise we use the equation of the constructor
where f is the focal length, p and q are the distance to the object and the image, respectively
They tell us the focal length f = 2.2 cm and that the image as far as it can go is q = 3.29 cm, let's find the position of the object that creates this image
1 / p = 1 / 2.2 - 1/3.29
1 / p = 0.15059
p = 6.64 cm
therefore the farthest distance from the object is 6.64 c
Answer:
(a) 2.34 s
(b) 6.71 m
(c) 38.35 m
(d) 20 m/s
Explanation:
u = 20 m/s, theta = 35 degree
(a) The formula for the time of flight is given by
T = 2.34 second
(b) The formula for the maximum height is given by
H = 6.71 m
(c) The formula for the range is given by
R = 38.35 m
(d) It hits with the same speed at the initial speed.
Answer:
a) , b)
Explanation:
a) According to the First Law of Thermodinamics, the system is not reporting any work, mass or heat interactions. Besides, let consider that such box is rigid and, therefore, heat contained inside is the consequence of internal energy.
The internal energy for a monoatomic ideal gas is:
Let assume that cubical box contains just one kilomole of monoatomic gas. Then, the temperature is determined from the Equation of State for Ideal Gases:
The thermal energy contained by the gas is:
b) The physical model for the cat is constructed from Work-Energy Theorem:
The speed of the cat is obtained by isolating the respective variable and the replacement of every known variable by numerical values: