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Sauron [17]
3 years ago
10

Consider two circular metal wire loops each carrying the same current I as shown below. In what region(s) could the net magnetic

field B be equal to zero? III IV .RS O None of them O 1, III, and v O III only O II and IV Submit Answer Tries 0/1
Physics
1 answer:
nadezda [96]3 years ago
7 0

Answer:

you counteract the Chromozones with the numerzones which contacts the specimen in the brain cells which then has voltage in the hand that connects with the wire then wallah

Explanation:

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An athlete stretches a spring an extra 28.6 cm beyond its initial length. how much energy has he transferred to the spring, if t
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PE = 0.5 × k × x²

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x stretch/compression of the spring
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Listening to the radio, you can hear two stations at once. Describe this wave interaction
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Actually says Pantazis, since their frequencies are so wildly different, brain waves don’t interfere with radio waves. Even if that was the case, brain waves are so weak, they are hardly measurable at all. For comparison, says Pantazis, “the magnetic field of the earth is just strong enough to move the needle of a compass. Signals from the brain are a billionth of that strength.”
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A 2.1 ✕ 103-kg car starts from rest at the top of a 5.9-m-long driveway that is inclined at 19° with the horizontal. If an avera
Lina20 [59]

Answer:

3.9 m/s

Explanation:

We are given that

Mass of car,m=2.1\times 10^3 kg

Initial velocity,u=0

Distance,s=5.9 m

\theta=19^{\circ}

Average friction force,f=4.0\times 10^3 N

We have to find the speed of the car at the bottom of the driveway.

Net force,F_{net}=mgsin\theta-f=2.1\times 10^3\times 9.8sin19-4.0\times 10^3

Where g=9.8 m/s^2

Acceleration,a=\frac{F_{net}}{m}=\frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}

v=\sqrt{2as}

v=\sqrt{2\times \frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}\times 5.9}

v=3.9 m/s

7 0
3 years ago
The fast train known as the TGV (Train à Grande Vitesse) that runs south from Paris, France, has a scheduled average speed of 21
andrezito [222]

Answer:

Explanation:

Given

average speed of train(v_{avg})=216 kmph\approx 60 m/s

Maximum acceleration=0.05g

Now centripetal acceleration is

a_c=\frac{v^2}{r}

0.05\times 9.8=\frac{60^2}{r}

r=7346.93 m

(b)Radius of curvature=900 m

therefore a_c=\frac{v^2}{r}

v=\sqrt{a_cr}

v=\sqrt{0.05\times 9.8\times 900}

v=\sqrt{441}=21 m/s

8 0
3 years ago
A unit of mass is ??
Effectus [21]
Hello,

Answer: kilogram

Further explaining: in science is used to measure weight of an object and used for accreditation.
Hope this helps!

3 0
3 years ago
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