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netineya [11]
3 years ago
8

Which of the following statements is true?

Chemistry
1 answer:
sattari [20]3 years ago
6 0
<h2>Answer:</h2>

The last statement is true. which is:

Mg is less reactive than Na because Mg has to lose one more electron than Na to complete its outermost shell.

<h3>Explanation:</h3>

Mg belongs to group II and Na belongs to group I.

Group II elements are less reactive than Group I elements. This is because it is more difficult to lose two electrons compared to losing just one electron.

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Find a substance that has a specific heat that is higher than liquid water and explain what it means.
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Liquid ammonia 
<span>liquid lithium </span>

<span>What it means? It means that, for the same amount of energy input, one grams of either of the above two will go up a lesser number of degrees Celsius than water will.</span>
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3 years ago
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What is the concentration of an alcl3 solution if 150. ml of the solution contains 550. mg of cl- ion?
valina [46]

The concentration of AlCl3 solution if 150 ml of the solution contains 550 mg of cl- ion is 0.0344 M


calculation


concentration = moles /volume in liters


volume in liters = 150 /1000= 0.15 L


number of moles calculation

write the equation for dissociation of Al2Cl3

that is AlCl3 ⇔ Al^3+ + 3 Cl ^-


find the moles of Cl^- formed

moles =mass/molar mass

mass in grams= 550/ 1000 =0.55 grams

molar mass of Cl^- =35.5 g/mol


moles is therefore= 0.55/35.5 =0.0155 moles


by use of mole ration betweem AlCl3 to Cl^- which is 1:3 the moles of AlCl3 is =0.0155 x 1/3= 5.167 x10^-3 moles



concentration of AlCl3 is therefore= 5.167 x10^-3/ 0.15 =0.0344 M

6 0
3 years ago
What did Thomson’s model of the atom include that Dalton’s model did not have?
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Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I
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Answer : The number of iron atoms present in each red blood cell are, 1.077\times 10^9

Explanation :

First we have to calculate the moles of iron.

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Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains 6.022\times 10^{23} number of iron atoms

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Now we have to calculate the number of iron atoms are present in each red blood cell.

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Number of iron atoms are present in each red blood cell = \frac{3.125\times 10^{22}}{2.90\times 10^{13}}

Number of iron atoms are present in each red blood cell = 1.077\times 10^9

Therefore, the number of iron atoms present in each red blood cell are, 1.077\times 10^9

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