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stepan [7]
3 years ago
13

1) The real basis of periodicity of elements is the electron

Chemistry
1 answer:
SIZIF [17.4K]3 years ago
6 0

Answer:

charge

Explanation:

explaining the house

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What volume of 1.50 M KBr is fromed ,using 15.6 mL of concentrated KBr with a molarity of 9.65 M?
Montano1993 [528]

Answer:

100.4mL

Explanation:

Using the following formula:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information in this question,

C1 = 1.50M

V1 = ?

C2 = 9.65 M

V2 = 15.6 mL

Using C1V1 = C2V2

V1 = C2V2/C1

V1 = (9.65 × 15.6) ÷ 1.5

V1 = 150.54 ÷ 1.5

V1 = 100.36 mL

Approximately, V1 = 100.4mL

4 0
3 years ago
3. The name of the functional group in the following compound
pashok25 [27]

Answer: a.) Methyl would be the answer.

Explanation:

7 0
3 years ago
What takes up the vast majority of space in an atom?
yKpoI14uk [10]

The answer is: a relatively large electron cloud.

Atom is composed of the nucleus and the electron cloud.

Protons (positive particles) and neutrons (neutral particles) are in the nucleus of an atom and electrons (negative particles) are in the electron cloud.

Nucleus is in the centar of the atom atom and electron cloud is surrounding it.

Atoms have their mass concentrated in a very small nucleus.


7 0
3 years ago
How many moles are there in 3.9 grams of potassium
polet [3.4K]

Answer:0.025576559594663 mole.

Explanation:

3 0
3 years ago
A sample of gas in a balloon has an initial temperature of 20. ∘C and a volume of 1.92×103 L . If the temperature changes to 68
morpeh [17]

Answer:

\boxed{2.23 \times 10^{3} \text{ L}}

Explanation:

The pressure is constant, so we can use Charles' Law.

\dfrac{ V_{1} }{T_{1}} = \dfrac{ V_{2} }{T_{2}}

Data:

V₁ = 1.92 × 10³ L; T₁ = 20 °C  

V₂ = ?;                 T₂ = 68 °C

Calculations:

(a) Convert temperatures to kelvins

T₁ = (20 + 273.15) K = 293.15 K

T₂ = (68 + 273.15) K = 341.15 K

(b) Calculate the volume

\dfrac{ 1.92 \times 10^{3}}{293.15} = \dfrac{ V_{2}}{341.15}\\\\6.550 = \dfrac{ V_{2}}{341.15}\\\\V_{2} = 6.550 \times 341.15 = 2.23 \times 10^{3} \text{ L}

The new volume of the gas is \boxed{2.23 \times 10^{3} \text{ L}}.

6 0
3 years ago
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