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azamat
3 years ago
15

The emission spectrum of iodine is shown below. A line spectra with 2 purple lines, 6 blue lines, 3 light blue lines, 3 green-bl

ue lines, 6 green lines, 8 yellow lines, 6 orange lines and 8 red lines. Which is the absorption spectrum? A line spectra with 4 purple lines, 6 blue lines, 3 light blue lines, 5 green-blue lines, 6 green lines, 7 yellow lines, 3 orange lines and 14 red lines. A line spectra with 6 purple lines, 9 blue lines, 6 light blue lines, 3 green-blue lines, 6 green lines, 2 yellow lines, 5 orange lines and 10 red lines. A line spectra with 2 black lines in purple, 6 black lines in blue, 3 black lines in light blue, 1 black line in green-blue, 10 black lines in green, 8 black lines in yellow, 6 black lines in orange and 8 black lines in red. A line spectra with 4 black lines in purple, 8 black lines in blue, 6 black lines in light blue, 3 black line in green-blue, 10 black lines in green, 4 black lines in yellow, 4 black lines in orange and 12 black lines in red.
Chemistry
2 answers:
Ilia_Sergeevich [38]3 years ago
5 0

Answer: is C. on Edge 2020

Explanation:

11Alexandr11 [23.1K]3 years ago
4 0

Answer:

it's b

Explanation:

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If 15 drops of ethanol from a medical dropper weight 0.60g, how many drops does it takes from a dropper to dispense 1.0ml of eth
Hoochie [10]

Answer : The number of drops it takes from a dropper to dispense 1.0 ml of ethanol is, 20 drops

Solution : Given,

Density of ethanol = 0.80 g/ml

Mass of ethanol = 0.60 g

First we have to calculate the volume of ethanol.

Formula used : Density=\frac{Mass}{Volume}

0.80g/ml=\frac{0.60g}{Volume}

Volume=\frac{0.60g}{0.80g/ml}=0.75ml

The volume of ethanol is, 0.75 ml

Now we have to calculate the number of drops it takes from a dropper to dispense 1 ml of ethanol.

As, the number of drops in 0.75 ml of ethanol = 15

So, the number of drops in 1.0 ml of ethanol = \frac{15}{0.75}\times 1.0=20

Therefore, the number of drops it takes from a dropper to dispense 1.0 ml of ethanol is, 20 drops

8 0
3 years ago
Which of these best describes heat transfer through conduction?
kozerog [31]

I'd go for D here. It also fits in with the idea of thermal expansion - as something is heated up, molecules vibrate and maybe collide. they vibrate with bigger amplitudes, so taking up more space, so expanding. maybe



4 0
3 years ago
Read 2 more answers
What is unchanged when a solution is diluted by the addition of solvent?
grin007 [14]

Answer:

The moles of solute

Explanation:

When you make a dilution, moles of solute does not change when you add solvent.

In concentrated solution, you have x moles of solute, that will be the same in the diluted solution.

Relation between molarity or volume of concentrated and diluted solutions is called, "dilution factor".

When you calculate the dilution factor: you use this formula

Molarity concentrated .  Concentrated volume = M diluted . Diluted volume

M concentrated / M Diluted = Diluted volume / Concentrated volume

5 0
3 years ago
Fabric A is used to rub a wooden rod. A second piece of Fabric A is used to rub an ebonite rod. It is observed that the wooden r
stepladder [879]
<h2>Answer:</h2>

<h3>What I think is : The protons are present at the centre of the atom with rotating electrons around it so when it is rubbed by fur the electrons get passed from the ebonite rod to the fur leaving the rod negatively charged</h3>

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6 0
3 years ago
<img src="https://tex.z-dn.net/?f=H_2PO_4%5E-%28aq%29%20%5Crightarrow%20H%5E%2B%28aq%29%20%2B%20HPO_4%5E%7B2-%7D%28aq%29" id="Te
klasskru [66]

Answer:

The pH of the buffer solution = 8.05

Explanation:

Using the Henderson - Hasselbalch equation;

pH = pKa₂ + log ( [HPO₄²-]/[H₂PO4⁻]

where pKa₂ = -log (Ka₂) = -log ( 6.1 * 10⁻⁸) = 7.21

Concentration of OH⁻ added = 0.069 M (i.e. 0.069 mol/L)

[H₂PO4⁻] after addition of OH⁻ = 0.165 - 0.069 = 0.096 M

[HPO₄²-] after addition of OH⁻ = 0.594 + 0.069 = 0.663 M

Therefore,

pH = 7.21 + log (0.663 / 0.096)

pH = 7.21 + 0.84

pH = 8.05

4 0
3 years ago
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