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geniusboy [140]
3 years ago
12

What is the molarity of a potassium triiodide solution, KI3(aq), if 30.00 mL of the solution is required to completely react wit

h 25.00 mL of a 0.500 M thiosulfate solution, K2S2O3(aq)
Chemistry
1 answer:
vfiekz [6]3 years ago
3 0

Answer:

The molarity is 0.203 M

Explanation:

Using the formula C(oxi) x V(oxi) / [C(red)  x  V(red)] = N(oxi) / N(red)

Where oxi and red means reducing agent and oxidising agent respectively.

C = Concentration, V = Volume and N = number of moles.

C(oxi) = 0.5 M

V(oxi) = mL

C(red) = ?

V(red) = 30mL

 Equation of reaction = 2K2S2O3 + KI3 = K2S4O6 + 3KI

so N(red) = 1 , N(oxi) = 2

from the equation above,

C(red) = 0.5 x 25 x 1 / (2 x 30)

          = 0.203 M.

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When iron metal reacts with oxygen, the reaction can form Fe2O3. Write a balanced chemical equation for this reaction, and find
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6.How many moles of gas would be in contained in a 11.2 L container that is at a
qaws [65]

0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.

<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>

The number of moles of a substance can be calculated using the following expression:

PV = nRT

Where;

  • p = pressure (atm)
  • v = volume (L)
  • n = number of moles
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  • T = temperature

0.75 × 11.2 = n × 0.0821 × 300

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Therefore, 0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.

Learn more about number of moles at: brainly.com/question/1190311

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