Answer:
30.17feet high
Step-by-step explanation:
Given the following
the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)
angle of elevation = 38°
Required
Height of the flagpole (opposite)
Using the SOH CAH TOA identity
Sin theta = opposite/hypotenuse
Sin 38 = H/49
H = 49sin38
H = 49(0.6157)
H = 30.17feet
Hence the flagpole is 30.17feet high
Answer:
B. perpendicular Hope this helps!
<h2>
Answer:</h2>
yes
<h3>
Step-by-step explanation:</h3>
This is a piecewise-defined function because it is defined by two or more equations over a specified domain is. The graph of this function is shown below. So this functions is continuous because its graph is a single unbroken curve. So the function is defined be the line 3x - 2 when x = 3 and the output here is y = 7
Answer:
<h2>
<em><u>Make</u></em><em><u> me</u></em><em><u> a</u></em><em><u> Brainlist</u></em><em><u> pls</u></em></h2>
Step-by-step explanation:
It's an Irregular polygon
D because one thousand nine hundred twenty divided by 8 equals two hundred and forty
