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IgorC [24]
3 years ago
14

Help me pleaseeeeeeeee

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
4 0

Answer:

(f o g)(x) = 4x^4 - 24x^2 + 37

(g o f)(x) = 16x^4 + 8x^2 - 2

Step-by-step explanation:

f(x) = 4x^2 + 1

g(x) = x^2 - 3

(f o g)(x) = f(g(x)) = f(x^2 - 3) = 4(x^2 - 3)^2 + 1 =

= 4(x^4 - 6x^2 + 9) + 1

= 4x^4 - 24x^2 + 37

(g o f)(x) = g(f(x)) = g(4x^2 + 1) = (4x^2 + 1)^2 - 3 =

= 16x^4 + 8x^2 - 2

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horrorfan [7]

Answer:

6 square root of 2

Step-by-step explanation:

sin theta = opposite / hypotenuse

sin 45 = 6/x

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If f(x)= 3-2 and g(x)=1/x+5 what is the vue of (f/g) (8)
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Answer:

The value of (f/g) (8) = -169

Step-by-step explanation:

<u>Step 1: explaining the question</u>

The quotient (f/g) is not defined at values of x ⇒  both the functions must be defined at a point for the combination to be defined.

⇒(f/g)(x) =(f(x)) / (g(x))

If f(x)= 3-2 and g(x)=1/x+5

⇒then according to the preceding formula: (f/g)(x) =(f(x)) / (g(x))

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The value of (f/g) (8) = -169

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Answer:

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Step-by-step explanation:

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