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IgorC [24]
2 years ago
14

Help me pleaseeeeeeeee

Mathematics
1 answer:
SIZIF [17.4K]2 years ago
4 0

Answer:

(f o g)(x) = 4x^4 - 24x^2 + 37

(g o f)(x) = 16x^4 + 8x^2 - 2

Step-by-step explanation:

f(x) = 4x^2 + 1

g(x) = x^2 - 3

(f o g)(x) = f(g(x)) = f(x^2 - 3) = 4(x^2 - 3)^2 + 1 =

= 4(x^4 - 6x^2 + 9) + 1

= 4x^4 - 24x^2 + 37

(g o f)(x) = g(f(x)) = g(4x^2 + 1) = (4x^2 + 1)^2 - 3 =

= 16x^4 + 8x^2 - 2

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Answer: x=20
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8 0
3 years ago
Which equation in point-slope form contains the point (–3, 5) and has slope –1? y + 3 = –1(x – 5) y – 5 = –1(x + 3) y – 3 = –1(x
andreev551 [17]

Answer:

y - 5 = -1(x + 3)

Step-by-step explanation:

Point slope form

y - y1 = m(x - x1) where m = slope and passing through point (x1 , y1)

In this case if the equation in point-slope form contains the point (–3, 5) and has slope –1 then the equation should be:

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6 0
3 years ago
I need explanation + answer.
finlep [7]

Answer:

C. 22,400.

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4 0
3 years ago
the center of a circle is on the line y=2x and the line x=1 is tangent to the circle at (1,6).find the center and the radius
Julli [10]

The radius and the center of the circle are 4 units and (1,2), respectively

<h3>How to determine the center and the radius?</h3>

The center of the circle is on

y = 2x and x = 1

Substitute x = 1 in y = 2x

y = 2 * 1

Evaluate

y = 2

This means that the center is

Center = (1, 2)

Also, we have the point of tangency to be:

(x, y) = (1, 6)

This point and the center have the same x-coordinate.

So, the distance between this point and the center is

d = 6 - 2

d = 4

This represents the radius

Hence, the radius and the center of the circle are 4 units and (1,2), respectively

Read more about circle equation at:

brainly.com/question/10618691

#SPJ1

6 0
2 years ago
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