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2 years ago

Can u help sold this

Mathematics

1 answer:

solong [7]2 years ago

4 0

Answer:

Step-by-step explanation:

To calculate the slope or gradient we use this formula:

Slope = y2-y1/x2-x1

(-3,2) = (x1, y1)

(4,2) = (x2, y2)

Slope = 2-2/4-(-3) = 0

Answer from Gauthmath

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dezoksy [38]

$\sqrt{3}(h-3000)=h$
 $(\sqrt{3}h-\sqrt{3}(3000)=h$
$(\sqrt{3}-1)h=\sqrt{3}(3000)$
$h=\frac{\sqrt{3}(3000)}{(\sqrt{3}-1)}$
$=\frac{\sqrt{3}(3000)}{(\sqrt{3}-1)}$
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2 years ago

Write an expression equal to 11^3 help please!! it’s due tonight

ASHA 777 [7]

Answer:

11 * 11 * 11

Step-by-step explanation:

11^3 is the same thing as 11*11*11

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3 years ago

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Which line is the line of reflection? A. a B. b C. c D. d

Leto [7]

The line of reflection is b

You can see it much easier if take away all the clutter. Redraw the diagram and take way a d and especially c.

You should be left with only line b and the two triangles. You can see it much easier if you do that. Then just look at the parallel lines of the triangles. They are right across from each other.

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2 years ago

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When lines meet or cross at the same point they are called

Luden [163]

I don’t know tbhhh .

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3 years ago

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WILL MARK BRAINLIEST!

Artist 52 [7]

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Dilation implies the triangle $\Delta XYZ$ stretched through the factor "2".

$m\angle Y = m\angle C = 90^{\circ} \leftarrow given \\\\$

right triangles:

$\Delta XYZ and \Delta ACB \\\\\angle X \cong \angle A \leftarrow given\\\\$

complementary angles:

$\angle X \ and\ \angle Z$

$m\angle Z = 90^{\circ} - m\angle X \\\\$

complementary angles:

$\angle A \ and\ \angle B$

$m\angle B = 90^{\circ} - m\angle A \\\\\therefore \\\\ \angle Z \cong \angle B \\\\\Delta XYZ \sim \Delta ACB \\\\$

Same triangles: proportional side are corresponding, congruence angles are respective.

$\sin \angle X = \frac{5}{5.59} \leftarrow given \\\\\sin\angle X = \frac{YZ}{XY} \\\\YZ = 5 (units) \rightarrow leg in \Delta XYZ \\\\XZ = 5.59 (units) \rightarrow hypotenuse \ in\ \Delta XYZ\\\\$

Calculating the length of leg XY:

$XY = \sqrt{((5.59)^2 - 52)} \cong 2.4996 (units)\\\\\frac{CB}{YZ} = 2 \leftarrow given \\\\CD = 2YZ = 2 \times 5 = 10 \ (units)\\\\\frac{AC}{XY} = 2 \leftarrow \ given\\\\AC = 2XY \cong 2 \times 2.4996 \cong 4.999\ (units)\\\\$

3 0

2 years ago