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Elden [556K]
2 years ago
10

PLS help ASAP I DONT have time to answer this, it also detects if it’s right or wrong.

Mathematics
1 answer:
Charra [1.4K]2 years ago
8 0

Answer:

48

Step-by-step explanation:

First of all find the scale.

36/9=4

So now you do 4 x 12

48

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Domain of f(x) = √6 - 2x is {x | -∞ < x ≤ 3}
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Use substitution to solve the system.<br> x=3y+5<br> 5x-4y=14<br> ______________<br> x=<br> y=
nataly862011 [7]
So what you do is go 5(3y+5)-4y=14 which equals 15y+25-4y=14 which turns into 11y+25=14 than you move the 25 over which equals 11y=-11 so y=-1 then you enter -1 in for y which looks like 5x-4(-1)=14 than you solve that which is 5x+4=14 than you move the 4 over and you get 5x=10 than x=2

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larisa [96]

Answer:

geometric because it is decreased by 1/27

Step-by-step explanation:

8 0
3 years ago
Using addition formula solve tan 15​
salantis [7]

Answer:

2 - \sqrt{3}

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = \frac{tanA-tanB}{1+tanAtanB} and the exact values

tan45° = 1 , tan60° = \sqrt{3} , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= \frac{tan60-tan45}{1+tan60tan45}

= \frac{\sqrt{3}-1 }{1+\sqrt{3} }

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + \sqrt{3} is 1 - \sqrt{3}

= \frac{(\sqrt{3}-1)(1-\sqrt{3})  }{(1+\sqrt{3})(1-\sqrt{3})  } ← expand numerator/denominator using FOIL

= \frac{\sqrt{3}-3-1+\sqrt{3}  }{1-3}

= \frac{-4+2\sqrt{3} }{-2}

= \frac{-4}{-2} + \frac{2\sqrt{3} }{-2}

= 2 - \sqrt{3}

3 0
3 years ago
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