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krek1111 [17]
3 years ago
8

Find the two numbers the quotient is between. Then estimate the quotient. 53 divided by 3

Mathematics
2 answers:
Anastasy [175]3 years ago
6 0
53/3=17.66. This number is between 17 and 18 but closest to 18 so the answer of the estimation of the quotient is 18.
Vesna [10]3 years ago
3 0
We can test various whole numbers and multiply them by 3 to see how close we can get to 53. 17 multiplied by 3 is 51, while 18 multiplied by 3 is 54. Since 53 is between 51 and 54, this means that 53/3 is between 17 and 18.
Furthermore, since 53 is closer to 54 than to 51, dividing it by 3 would put it closer to 18 than to 17.

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Solve the simultaneous equations<br> 5y−4x=8<br> y+x=7<br><br> x= ?<br> y= ?
inna [77]

Answer:

x=3 y=4

Step-by-step explanation:

5(4)=20

4(3)= 12

20-12=8

4+3=7

4 0
3 years ago
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HELP MEEEEEEEEEEEE<br><br><br> (please don't put a link or i don't know)
Leviafan [203]

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Step-by-step explanation:

7 0
2 years ago
Factor the expression 20k + 50
Yuliya22 [10]
Answer is 10(2k+5)

-----------------------------------

Work Shown:

20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)

Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer

Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
4 0
3 years ago
I'm not sure how to do this! 50 points?
Rus_ich [418]

Answer:

MOP=33

Step-by-step explanation:

MOP + MON = NOP

Substitute what we know

MOP = 3x-3

MON = 4x+9  

NOP = 90   right angle

3x-3+4x+9 = 90

Combine like terms

7x+6 =90

Subtract 6 from each side

7x+6-6=90-6

7x = 84

Divide each side by 7

7x/7 = 84/7

x =12

We need to find MOP

MOP = 3x-3

        =3(12)-3

         36-3

        33

6 0
3 years ago
Read 2 more answers
Extension question (provide a full explanation of your method(s):
Volgvan

Answer:

Ann has little chance to win if she is presented with 4 counters.

Ann can always win from a pile of 6 counters.

(both are explained below)

Step-by-step explanation:

If Ann  is presented with 4 counters, and

1. if she takes out 3, she will lose since the opponent will  pull out 1 and the last one.

2. if she takes 2 her opponent will take out 1 and she can't pull out the last 1 since her opponents last move was to pull out 1  counter so she will lose.

3. If she takes out 1 and her opponent takes out 3 in the next move she loses.

but if instead of 3 her opponent takes out 2 and in the last move Ann takes out the last 1  then she will win.

So, If Ann is presented with 4 counters she has little chance to win provided in the move just before, her opponent didn't move 1 counter.

Now,

if there is 6 counters to Ann, and

1., if Ben's  previous move was 1 then Ann can win if she takes out 3 or 2.

If she takes out 3 Ben can take out 1 or 2 and in the last move she will take out 2 or 1 (respectively) and winning the game.

If she takes out 2 Ben can  take out 1 or 3 and in the last move Ann wins by pulling out 3 or 1 respectively.

2. if Ben's  previous move was 2 then Ann can win if she takes out 1 or 3.

If she takes out 1 Ben can take out 2 or 3 and in the last move she will take out 3 or 2(respectively) and winning the game.

If she takes out 3 Ben can  take out 1 or 2 and in the last move Ann wins by pulling out 2 or 1 respectively.

2. if Ben's  previous move was 3 then Ann can win if she takes out 1 or 2.

If she takes out 1 Ben can take out 2 or 3 and in the last move she will take out 3 or 2(respectively) and winning the game.

If she takes out 2 Ben can  take out 1 or 3 and in the last move Ann wins by pulling out 3 or 1 respectively.

 

 

7 0
3 years ago
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