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il63 [147K]
2 years ago
15

The midpoint of AB is M (2,0). If the coordinates of A are, (-3, 3), what are the coordinates of B?​

Mathematics
1 answer:
gregori [183]2 years ago
5 0

Given:

M is the midpoint of AB.

M(2,0) and A(-3, 3).

To find:

The coordinates of point B.

Solution:

Midpoint formula:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Let the coordinates of point B are (a,b). Then, using the midpoint formula, we get

(2,0)=\left(\dfrac{-3+a}{2},\dfrac{3+b}{2}\right)

On comparing both sides, we get

\dfrac{-3+a}{2}=2

-3+a=2\times 2

a=4+3

a=7

And,

\dfrac{3+b}{2}=0

3+b=0

3+b-3=0-3

b=-3

Therefore, the coordinates of point B are (7,-3).

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Answer:

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Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

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\sqrt[3]{x}\cdot\sqrt[3]{x^2}

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Apply formula

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\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

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