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3 years ago

PQ is tangent to the circle at C. In the circle, m (The figure is not drawn to scale.)

Mathematics

1 answer:

Yuri [45]3 years ago

5 0

Answer:

65°

Step-by-step explanation:

From the figure we can see a circle.

It is given that, measure of arc AD = 80° therefore m<ACD = 80/2 = 40°

Also m<D = 75°

<u>To find the measure of <DCQ</u>

We know that, an angle made by a tangent and chord is equal to the angle made by the angle made by the chord on other side of the circle.

Here m<DCQ = m<CAD

By using angle sum property,

m<CAD + m<ACD + m<D = 180

m<CAD + 40 + 75 = 180

m<CAD + 115 = 180

m<CAD = 180 - 115 = 65°

Therefore m<DCQ = m< CAD = 65°

The correct answer is third option.

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2 years ago

Find f(k - 1) when f(x) = 5x^2+ 4x – 5.

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3 years ago

Refer to the following information from a frequency distribution for "heights of college women" recorded to the nearest inch:The

valkas [14]

Answer: Therefore, Option 'A' is correct.

Step-by-step explanation:

Since we have given that

Two class midpoints are 62.5 and 65.5

So, the class interval would be

$65.5-62.5=3$

So, the limits of lower class are $x_1\ and\ x_2$

The limits of upper class are $x_2\ and\ x_3$

So, it becomes,

$\dfrac{x_1+x_2}{2}=62.5\\\\x_1+x_2=62.5\times 2=125$

and

$\dfrac{x_2+x_3}{2}=65.5\\\\x_2+x_3=65.5\times 2=131$

Since we have given that interval is 3.

So, $x_2-x_1=3\ and\ x_3-x_2=3$

So, by solving all the questions, we get that

$x_2+x_1=125\\\\x_2-x_1=3\\\\-------------------------\\\\2x_2=128\\\\x_2=64\\\\x_2-x_1=3\\\\64-x_1=3\\\\x_1=61\\\\and\\\\x_3-x_2=3\\\\x_3-64=3\\\\x_3=67$

Hence, the class limits would be

(61,64) and (64,67).

And the class limits of lowest class are 61 and 64.

Therefore, Option 'A' is correct.

4 0

3 years ago