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2 years ago

Can someone please help me with this question.

Mathematics

1 answer:

Ber [7]2 years ago

4 0

Answer:

square root of 2

Step-by-step explanation:

Sides are 1 and 1 and the hypotenuse is the longest side (opposite the right angle)

We can use pythagerouses theorem : a^2+b^2=c^2

this means that 1^2+1^2=c^2

1+1=c^2

2=c^2

c=2/sqrt

c is the square root of 2

the hypotenuse is the square root of 2

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Two line are ___ if and only if they lie in the same plane and do not intersect, and two lines are __ if and only if they lie in

Vilka [71]

the answer is C, I think because parallel lines never touch

6 0

2 years ago

An architect wants to draw a rectangle with a diagonal of 13 centimeters. The length of the rectangle is to be 3 centimeters mor

butalik [34]

Answer:

The rectangle is 3.2 cm by 12.6 cm

Step-by-step explanation:

See attached image for a diagram.

Choose w to represent the width because the length is described by referring to the width: it's 3 more than (add 3) triple (multiplied by 3) the width.

Length = 3w + 3

The diagonal forms two right triangles, each with leg = w, other leg = 3w + 3, hypotenuse = 13.

The Pythagorean Theorem says $(\text{leg})^2+(\text{leg})^2=(\text{hypotenuse})^2$ so

$w^2+(3w+3)^2=13^2\\\\w^2+9w^2+18w+9=169\\\\10w^2+18w-160=0\\\\5w^2+9w-80=0\\$

Now solve using the Quadratic Formula with $a=5,\,b=9,\,c=-80$ .

$w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\w=\frac{-9\pm\sqrt{81+1600}}{10}\\\\w=\frac{-9\pm\sqrt{1681}}{10}\\\\w=\frac{-9\pm41}{10}\\\\w=-5\text{ or }w=3.2$

The negative root makes no sense as a distance, so the width of the rectangle is 3.2 cm. The length is 3(3.2) + 3 = 12.6 cm.

5 0

2 years ago

The Arizona Cardinals won ten games out

goldenfox [79]

Answer:

80 games

Step-by-step explanation:

10wins/16 games=50 wins/? games

10 times 5=50 so 16 times 5 =80

10.g=16.50

10/g=800/10

g=80 games

7 0

3 years ago

A right cylinder has a radius of r inches and height of 2r inches.

lys-0071 [83]

Answer:

Part a) The lateral area is $4r^{2} \pi \ in^{2}$

Part b) The area of the two bases together is $2r^{2} \pi\ in^{2}$

Part c) The surface area is $6r^{2} \pi\ in^{2}$

Step-by-step explanation:

we know that

The surface area of a right cylinder is equal to

$SA=LA+2B$

where

LA is the lateral area

B is the area of the base of cylinder

we have

$r=r\ in$

$h=2r\ in$

Part a) Find the lateral area

The lateral area is equal to

$LA=2\pi rh$

substitute the values

$LA=2\pi r(2r)$

$LA=4r^{2} \pi\ in^{2}$

Part b) Find the area of the two bases together

The area of the base B is equal to

$B=r^{2} \pi\ in^{2}$

the area of the two bases together is

$2B=2r^{2} \pi\ in^{2}$

Part c) Find the surface area of the cylinder

$SA=LA+2B$

we have

$LA=4r^{2} \pi\ in^{2}$

$2B=2r^{2} \pi\ in^{2}$

substitute

$SA=4r^{2} \pi+2r^{2} \pi=6r^{2} \pi\ in^{2}$

4 0

3 years ago

Read 2 more answers

Please help please please please

Iteru [2.4K]

Answer:

Step-by-step explanation:

40 degrees, then 40/360

40/360 is equal to 1/9

1/9 times pi times times r^2

just find r and multiply all together, thats my best answer cause my IQ is like 60

4 0

3 years ago