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cluponka [151]
2 years ago
11

Can someone please help me with this question.

Mathematics
1 answer:
Ber [7]2 years ago
4 0

Answer:

square root of 2

Step-by-step explanation:

Sides are 1 and 1 and the hypotenuse is the longest side (opposite the right angle)

We can use pythagerouses theorem : a^2+b^2=c^2

this means that 1^2+1^2=c^2

1+1=c^2

2=c^2

c=2/sqrt

c is the square root of 2

the hypotenuse is the square root of 2

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Two line are ___ if and only if they lie in the same plane and do not intersect, and two lines are __ if and only if they lie in
Vilka [71]

the answer is C, I think because parallel lines never touch

6 0
2 years ago
An architect wants to draw a rectangle with a diagonal of 13 centimeters. The length of the rectangle is to be 3 centimeters mor
butalik [34]

Answer:

The rectangle is 3.2 cm by 12.6 cm

Step-by-step explanation:

See attached image for a diagram.

Choose <em>w</em> to represent the width because the length is described by referring to the width:  it's 3 more than (add 3) triple (multiplied by 3) the width.

Length = 3w + 3

The diagonal forms two right triangles, each with leg = <em>w</em>, other leg = 3<em>w</em> + 3, hypotenuse  =  13.

The Pythagorean Theorem says (\text{leg})^2+(\text{leg})^2=(\text{hypotenuse})^2 so

w^2+(3w+3)^2=13^2\\\\w^2+9w^2+18w+9=169\\\\10w^2+18w-160=0\\\\5w^2+9w-80=0\\

Now solve using the Quadratic Formula with a=5,\,b=9,\,c=-80.

w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\w=\frac{-9\pm\sqrt{81+1600}}{10}\\\\w=\frac{-9\pm\sqrt{1681}}{10}\\\\w=\frac{-9\pm41}{10}\\\\w=-5\text{ or }w=3.2

The negative root makes no sense as a distance, so the width of the rectangle is 3.2 cm. The length is 3(3.2) + 3 = 12.6 cm.

5 0
2 years ago
The Arizona Cardinals won ten games out
goldenfox [79]

Answer:

80 games

Step-by-step explanation:

10wins/16 games=50 wins/? games

10 times 5=50 so 16 times 5 =80

10.g=16.50

10/g=800/10

g=80 games

7 0
3 years ago
A right cylinder has a radius of r inches and height of 2r inches.
lys-0071 [83]

Answer:

Part a) The lateral area is 4r^{2} \pi \ in^{2}

Part b) The area of the two bases together is 2r^{2} \pi\ in^{2}

Part c) The surface area is 6r^{2} \pi\ in^{2}

Step-by-step explanation:

we know that

The surface area of a right cylinder is equal to

SA=LA+2B

where

LA is the lateral area

B is the area of the base of cylinder

we have

r=r\ in

h=2r\ in

Part a) Find the lateral area

The lateral area is equal to

LA=2\pi rh

substitute the values

LA=2\pi r(2r)

LA=4r^{2} \pi\ in^{2}

Part b) Find the area of the two bases together

The area of the  base B is equal to

B=r^{2} \pi\ in^{2}

so

the area of the two bases together is

2B=2r^{2} \pi\ in^{2}

Part c) Find the surface area of the cylinder

SA=LA+2B

we have

LA=4r^{2} \pi\ in^{2}

2B=2r^{2} \pi\ in^{2}

substitute

SA=4r^{2} \pi+2r^{2} \pi=6r^{2} \pi\ in^{2}

4 0
3 years ago
Read 2 more answers
Please help please please please
Iteru [2.4K]

Answer:


Step-by-step explanation:

40 degrees, then 40/360

40/360 is equal to 1/9

1/9 times pi times times r^2  

just find r and multiply all together, thats my best answer cause my IQ is like 60

4 0
3 years ago
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