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3 years ago

15

Kevin leans a 26-foot ladder against a wall so that it forms an angle of 71^{\circ} ∘ with the ground. How high up the wall does

the ladder reach? Round your answer to the nearest hundredth of a foot if necessary.

1 answer:

Rashid [163]3 years ago

8 0

<h2>Answer:≈24.58</h2>

Step-by-step explanation:

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8x(12+7-9)-(4+10) what’s the answer

navik [9.2K]

Equation- 8x(12+7-9)-(4+10)

Answer- 80x−14

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1 year ago

Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 )left parenthesis, 0, comma

steposvetlana [31]

Answer:

$\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }$

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) $\frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }$ .

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

$\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }$

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3 years ago

Complete the square to determine the minimum or maximum value of the function defined by the expression.

FrozenT [24]

Answer:

Option D. minimum value at −38

Step-by-step explanation:

we have

$x^{2}-12x-2$

Let

$y=x^{2}-12x-2$

Complete the square

$y+2=x^{2}-12x$

$y+2+36=(x^{2}-12x+36)$

$y+38=(x^{2}-12x+36)$

$y+38=(x-6)^{2}$

$y=(x-6)^{2}-38$ ------> equation of a vertical parabola in vertex form

The vertex is the point $(6,-38)$

The parabola open upward-----> the vertex is a minimum

therefore

minimum value at −38

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2 years ago

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3 years ago

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Slav-nsk [51]

Answer:

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2 years ago