<span>Evaluate when a = 8 and b = 4.
ab^2
a−b
ab² = (8)(4)² = 8*16= 128
a - b = 8 - 4 = 4 </span>
Two events are occurring:
1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3
Probability of getting an odd number = 3/6
2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2
The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12
Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario.
So correct answer is option C
Answer:
7 3/4+(-1/2)
Step-by-step explanation:
Answer:
30
Step-by-step explanation:
15x2=30
10x3=30
