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jenyasd209 [6]
3 years ago
15

7. What initial volume of water vapor would have been present at 310 K if the volume now

Chemistry
1 answer:
Alexxx [7]3 years ago
6 0

Answer:

206.3cm³

     

Explanation:

Given parameters:

Initial temperature  = 310K

Final volume  = 360cm³

Final temperature  = 541K

Unknown:

Initial volume  = ?

Solution:

To solve this problem we apply the Charles's law which states that "the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant".

  Mathematically;

     \frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

V and T are volume and temperature

1 and 2 are initial and final states

 Insert the parameters and solve for V₁;

                    \frac{V_{1} }{310}  = \frac{360}{541}  

                    V₁   = 206.3cm³

     

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When we add 0.33L of KOH only the HCl solution will be neutralized. When we add <u>1.4 L</u> of KOH, all of the acid (the HCl and H2SO4 solution) will be neutralized.

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<u>Step 1:</u> Data given

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<u>Step 4:</u> The balanced neutralization reaction of KOH with HCl can be written as:

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The mole ratio is 1:1

This means to neutralize 0.05 moles HCl, we need 0.05 moles KOH

<u>Step 5:</u> The balanced neutralization reaction of KOH with H2SO4 can be written as:

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To neutralize the H2SO4 solution: 0.210 moles / 0.150 M = 1.4 L KOH needed

When we add 0.33L of KOH the HCl solution will be neutralized. When we add 1.4 L of KOH the HCl and H2SO4 solution will be neutralized.

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