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jenyasd209 [6]
3 years ago
15

7. What initial volume of water vapor would have been present at 310 K if the volume now

Chemistry
1 answer:
Alexxx [7]3 years ago
6 0

Answer:

206.3cm³

     

Explanation:

Given parameters:

Initial temperature  = 310K

Final volume  = 360cm³

Final temperature  = 541K

Unknown:

Initial volume  = ?

Solution:

To solve this problem we apply the Charles's law which states that "the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant".

  Mathematically;

     \frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

V and T are volume and temperature

1 and 2 are initial and final states

 Insert the parameters and solve for V₁;

                    \frac{V_{1} }{310}  = \frac{360}{541}  

                    V₁   = 206.3cm³

     

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3 years ago
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Andrew [12]

Answer:

Group 1 and 2 elements

Explanation:

Nitrogen, a non-metal will form ionic bonds with most group 1 and group 2 metals on the periodic table.

How does ionic bonds form?

  • They are bonds formed between a highly electronegative specie and one with very low electronegativity.
  • As such, ionic bonds forms between metals and non-metals
  • In this bond type, the metal due to its electropositive nature will transfer electrons to the non-metals for it to gain.
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Most metals in group 1 and 2 fits in this description. Some of them are calcium, magnesium, lithium, Barium e.t.c.

It mostly favors group 2 metals.

5 0
3 years ago
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il63 [147K]

Answer is: the ratio of the effusion rate is 1.59 : 1.

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rate of effusion of carbon monoxide gas = 1/√28.

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rate of effusion of carbon monoxide : rate of effusion of chlorine =

= 0.189 : 0.119 / ÷0.119.

rate of effusion of carbon monoxide : rate of effusion of chlorine = 1.59 : 1.

4 0
3 years ago
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Another example, water (H₂O) is made of two hydrogen atoms and one oxygen atom:  

m(H) : m(O) = 2·1 : 16 = 1: 8.

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