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2 years ago

7. What initial volume of water vapor would have been present at 310 K if the volume now

Chemistry

1 answer:

Alexxx [7]2 years ago

6 0

Answer:

206.3cm³

Explanation:

Given parameters:

Initial temperature = 310K

Final volume = 360cm³

Final temperature = 541K

Unknown:

Initial volume = ?

Solution:

To solve this problem we apply the Charles's law which states that "the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant".

Mathematically;

$\frac{V_{1} }{T_{1} }$ = $\frac{V_{2} }{T_{2} }$

V and T are volume and temperature

1 and 2 are initial and final states

Insert the parameters and solve for V₁;

$\frac{V_{1} }{310}$ = $\frac{360}{541}$

V₁ = 206.3cm³

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