The moles of oxygen that are needed to produce 13.7 moles of carbon dioxide is 21.17 moles of Oxygen
<u><em>calculation</em></u>
2 C₆H₁₂O + 17 O₂ → 12 CO₂ +12 H₂O
The moles of O₂ is determined using the mole ratio
that is for given equation above O₂ : Co₂ is 17 :12
therefore the moles of O ₂= 13.7 moles x 17/12 =21.17 moles
Is it inches millimeters meters ?
Answer:
-75 cm^3/min
Explanation:
Given from Boyle's law;
PV=C
From product rule;
VdP/dt + PdV/dt = dC/dt
but dC/dt = 0, V= 500 cm^3, P= 200kPa, dP= 30kPa/min
PdV/dt = dC/dt - VdP/dt
dV/dt = dC/dt - VdP/dt/ P
substituting values;
dV/dt = 0 - (500 * 30)/200
dV/dt = -75 cm^3/min
