Equation 3x-5=-2x+ 10?<br> O<br> 0<br> x= 5<br> -5 = x<br> -15 = -5x<br> -5x = 15

Solar radiation provides more heat and cleaner than near the pools on Earth the greatest amount of heat is moved away from the e

Rashid [163]

Answer:

Ocean Currents

Explanation:

The correct answer is Ocean currents.

When the earth receives solar radiation, a large fraction of this incident radiation is usually absorbed by the oceans and the seas, which become warm. Usually, equitorial regions are the ones that have this phenomenon. Now, when ocean currents are flowing from the equator, they usually carry this warm water with them thereby moving the greatest amount of heat from the equator on its way out.

For example, In the Pacific Ocean, there is a current known as Alaska Current that carries warm water in the northward direction thereby making Anchorage which is Alaska's largest city to have a much mild weather than the inland areas with the same latitude.

4 0

3 years ago

60 kg of fuel was completely burnt for an experiment. The amount of heat energy was found to be 180000KJ. Calculate calorific va

FrozenT [24]

Answer:

3000 kJ/kg

Explanation:

The calorific value of a substance is the amount of heat produced per unit mass by the combustion of the substance.

It is given by:

$C=\frac{Q}{m}$

where

Q is the amount of heat released

m is the mass of the fuel

In this problem, we have:

m = 60 kg is the mass of fuel

$Q=180,000 kJ$ is the amount of heat released

Therefore, the calorific value of the fuel is:

$C=\frac{180,000}{60}=3000 kJ/kg$

6 0

3 years ago

How much heat energy would be released if 78.1 g of water at 0.00 °c were converted to ice at −57.1 °c. give your answer as a po

kolezko [41]

To convert 78.1 g of water at 0° C to Ice at -57.1°C; we can do it in steps;
1. Water at 0°C to ice at 0°C
The heat of fusion of ice is 334 J/g;
Heat = 78.1 × 334 = 26085.4 Joules
2. Ice at 0°C to -57.1°C
Specific heat of ice is 2.108 J/g
Heat = 78.1 × 2.108 J/g = 164.6348 Joules
Thus the total heat energy released will be; 26085.4 + 164.6348
= 26250.0348 J or 26.250 kJ

3 0

3 years ago

Directions: Perform the Assessment in Module 7 because that will serve as your Performance Task for Module 5, 6 & 7. Kindly

garik1379 [7]

please put your question completely....

8 0

3 years ago

PLEASE HELP CHEMISTRY

eduard

When sodium carbonate is dissolved in water, the equation is $Na_2CO_3 (s) --- > 2Na^+ (aq) + CO_3^{2-} (aq)$ .

When carbon dioxide is placed in water, aqueous carbon dioxide is formed: $CO_2 (g) --- > CO_2(aq)$

<h3>Dissolution of compounds in water</h3>

Some compounds are water-soluble, some are just partially soluble, while others are insoluble in water. Some soluble or partially soluble substances dissociate in water into their component ions. These substances are said to be ionic.

Sodium carbonate, like every other sodium salt, is soluble in water. It dissolves in water to form an aqueous solution of sodium carbonate.

While in solution, sodium carbonate dissociates into its component ions according to the following equation:

$Na_2CO_3 (s) --- > 2Na^+ (aq) + CO_3^{2-} (aq)$

Carbon dioxide, on the other hand, does not dissociate in water. Instead, it dissolves in water where most of it remains as aqueous carbon dioxide in equilibrium with a small amount of hydronium ion and hydrogen carbonate ion.

Since the hydronium and hydrogen carbonate ions formed are so minute, the equation of the reaction can be written as: $CO_2 (g) --- > CO_2(aq)$

More on the dissolution of substances can be found here: brainly.com/question/28580758

#SPJ1

7 0

1 year ago

Equation 3x-5=-2x+ 10? O 0 x= 5 -5 = x -15 = -5x -5x = 15