3 years ago

Solve for b if R = x(A + B)

Chemistry

1 answer:

Tatiana [17]3 years ago

7 0

This is what I got. Hope it helps :)

You might be interested in

In a different experiment, the student uses a calorimeter which is perfectly insulated. She fills the calorimeter with 100.0 g o

alexdok [17]

Answer:

Explanation:

Mg + 2HCl = Mg Cl₂ + H₂

.594 g = .594 / 24.3

= .02444 mole

Heat evolved = msΔ T , m is mass of water ( solvant ) , s is specific heat of water , Δ T is rise in temperature

= 100 x 4.2 x ( 41.83 - 25 )

= 7068.6 J

.02444 mole of Mg evolves 7068.6 J of heat

1 mole of Mg evolves 7068.6 /.02444 J

= 289222.6 J

= 289 kJ .

Molar heat enthalpy = 289 kJ .

8 0

3 years ago

Consider the group a1 element sodium atomic number 11, the group 3a element aluminum atomic number 13, and the group 7a element

Akimi4 [234]

According to there chemical properties

7 0

3 years ago

Is electrical conductivity an extensive property or an intensive property?

Thepotemich [5.8K]

Your Answer Will Be Intensive Property

8 0

3 years ago

Question 12 of 25

Tomtit [17]

Answer:

Explanation:

All atoms are divisible

6 0

3 years ago

Identify the number of moles in 369 grams of calcium hydroxide. Use the periodic table and the polyatomic ion resource.

topjm [15]

Answer : The number of moles in 369 grams of calcium hydroxide is, 4.98 moles

Explanation : Given,

Mass of calcium hydroxide = 369 g

Molar mass of calcium hydroxide = 74.093 g/mole

Formula used :

$\text{Moles of calcium hydroxide}=\frac{\text{Mass of calcium hydroxide}}{\text{Molar mass of calcium hydroxide}}$

Now put all the given values in this formula, we get the moles of calcium hydroxide.

$\text{Moles of calcium hydroxide}=\frac{369g}{74.093g/mole}=4.98mole$

Therefore, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles

7 0

3 years ago