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PolarNik [594]
3 years ago
8

Potassium chlorate, KClO3, decomposes when heated to produce potassium chloride and oxygen gas. If 2.50 grams of KCLO3 were heat

ed in a test tube, how many grams of oxygen gas should be given off?
Chemistry
2 answers:
Neporo4naja [7]3 years ago
7 0

Answer:

0.98 g O_{2}

Explanation:

  • O_{2} = 2.5 g KCLO3 x \frac{1 mol KCLO3}{122.5 g KCLO3}  * \frac{3 mol O2}{2 mol KCLO3} * \frac{32 g O2}{1 mol O2}  = 0.98 g O2
dimulka [17.4K]3 years ago
3 0
Potassium chlorate has a molas mass of 122.55 g/mol. So, 2.50 g of KClO3 is,
2.5 g / (122.55 g/mol) = 0.0204 moles KClO3

The balanced chemical reaction is this:
2KClO3 ----> 2KCl + 3O2

So, for every 2 moles of KClO3, 3 moles of O2 forms. Using this ratio,
0.0204 moles KClO3 (3/2) = 0.0306 moles O2.

Converting moles of O2 to grams of O2:
0.0306 moles (16 g/mol) = 0.4896 grams

Therefore, around 0.49 grams of O2 will be formed if 2.50 g of KClO3 decomposed.

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Murljashka [212]

1) Dawn dish soap has a density of 1.06 g/mL. If the mass of a sample of the liquid is 1.00 g what is the volume?

Answer:

v = 0.94 mL

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Given data:

Density of soap =  1.06 g/mL.

Mass  = 1 g

Volume = ?

Solution:

d = m/v

v = m/d

v = 1 g/1.06 g/mL

v = 0.94 mL

2) Maple syrup has a density of 1.37 g.mL. What is the mass of 1.0 L of the maple syrup?

Answer:

m = 1370 g

Given data:

Density of soap =  1.37 g/mL.

Mass  = ?

Volume = 1.0 L ( 1000 mL)

Formula:

D=m/v

D= density

m=mass

V=volume

Solution:

d = m/v

m = d × v

m = 1.37 g/mL  ×  1000 mL

m = 1370 g

3) The density of gasoline is 0.754 g/mL. A drop of gasoline has a mass of 22 g what is the volume?

Answer:

v = 29.2 mL

Given data:

Density of soap =  0.754 g/mL.

Mass  = 22 g

Volume = ?

Formula:

D=m/v

D= density

m=mass

V=volume

Solution:

d = m/v

v = m/d

v = 22 g/0.754 g/mL

v = 29.2 mL

6 0
3 years ago
A 1 liter solution contains 0.247 M nitrous acid and 0.329 M sodium nitrite. Addition of 0.271 moles of calcium hydroxide will:
Inessa05 [86]

Answer:

a. Raise the pH slightly

Explanation:

We know that

Pka of HNO2/KNO2 =3.39

Moles of HNO2 in the buffer=0.247 mol/L×1L=0.247 moles

Moles of NO2-=0.329mol/L×1L=0.329 moles

If 0.271 moles of Ca(OH)2 is added it will neutralise 0.136 moles of acid ,HNO2,remaining HNO2=0.247-0.136=0.111 moles

Moles of NO2- will increase as 0.0333 moles Ca(NO)2 will be formed =0.0333+0.036=0.0693 moles

pH=pka+log [base]/[acid]      {henderson -hasselbach equation}

=3.39+log (0.0693/0.0317)=3.39+0.34=3.73

pH=3.73

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3 years ago
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jeyben [28]

Answer:

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Explanation:

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3 years ago
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