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3 years ago

What is the range of y = -x2 - 2x + 3?

Mathematics

2 answers:

Firlakuza [10]3 years ago

6 0

The answer is x2-5 and the reason is that if you carry the two then add the four this is the answer

swat323 years ago

4 0

Answer:

$y = - {x}^{2} - 2x + 3 \\ y = (x + 3)(x - 1) \\ range \: = - 3 \leqslant x \leqslant 1$

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What's proportional reasoning and what does it mean for something to be proportional?

qwelly [4]

Proportional reasoning is the ability to compare two things using information given, in math, it is most frequently defined as comparing quantities. For something to be proportional, there has to a constant ration of another quantity.

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3 years ago

If Vector u=(5,-7) and v=(-11,3), 2v-6u=_____ and ||2v-6u||≈_____

Sauron [17]

<h2>Answer:</h2>

$2\vec{v}-6\vec{u}=(-52,48) \\ \\ ||2\vec{v}-6\vec{u}||=75.28}$

<h2>Step-by-step explanation:</h2>

In this problem we have two vectors:

$\vec{u}=(5,-7) \ and \ \vec{v}=(-11,3)$

So we need to find two things:

$2\vec{v}-6\vec{u}$

and:

$||2\vec{v}-6\vec{u}||$

FIRST:

In this case we have the multiplication of vectors by scalars. A scalar is a simple number, so:

$2\vec{v}-6\vec{u} \\ \\ Replace \ \vec{v} \ and \ \vec{u} \ by \ the \ given \ vectors: \\ \\ 2(-11,3)-6(5,-7) \\ \\ Multiply \ each \ component \ by \ the \ corresponding \ scalar:\\ \\ (2\times (-11),2\times 3)+(-6\times 5,-6\times (-7)) \\ \\ (-22,6)+(-30,42) \\ \\ Sum \ of \ vectors: \\ \\ (-22-30,6+42) \\ \\ \therefore \boxed{(-52,48)}$

SECOND:

If we name:

$\vec{w}=2\vec{v}-6\vec{u}$

Then, $||2\vec{v}-6\vec{u}||$ is the magnitude of the vector $\vec{w}$ . Therefore:

$||\vec{w}||=||2\vec{v}-6\vec{u}|| \\ \\ ||\vec{w}||=||(-52,48)|| \\ \\ ||\vec{w}||=\sqrt{(-58)^2+48^2} \\ \\ ||\vec{w}||=\sqrt{3364+2304} \\ \\ ||\vec{w}||=\sqrt{5668} \\ \\ \boxed{||\vec{w}||=75.28}$

5 0

3 years ago

Read 2 more answers

Which shows one way to determine the factors of x3 11x2 – 3x – 33 by grouping? x2(x 11) 3(x – 11) x2(x – 11) – 3(x – 11) x2(x 11

Aloiza [94]

The one way to determine factors of x³ + 11x² – 3x – 33 will be $x^2(x+11)-3(x+11)_$ .

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The steps involved in the factorization are;

1. For each pair of parentheses, we create a common factor.

2. We use x2 as a common factor for the first parenthesis.

3. We use common factor 3 for the second parenthesis.

$x^3 + 11x^2 - 3x -33 \\\\ x^2(x+11)-3(x+11)_$