1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mnenie [13.5K]
3 years ago
6

How is volume calculated given mass and density? (4 points)

Chemistry
2 answers:
AysviL [449]3 years ago
5 0

Answer: 5.6

Explanation: 3 over the 4 to the 7;2.4    you get 5.6

lianna [129]3 years ago
3 0
It’s mass divided by volume. A helpful thing to use is the triangle of power where the M (mass) is on top and the D(density) and v(volume) is on the bottom.
You might be interested in
Simple question ill name u brainiest
BigorU [14]

Answer:

Test tube :)

Explanation:

4 0
3 years ago
Read 2 more answers
What types of waves are produced by a jackhammer?
fomenos
Options? I'm thinking P Waves.

4 0
3 years ago
Read 2 more answers
If 650. grams of C6H12O6 (FW 180.16) reacts with 650. grams of O2 (FW 32.00) in cellular respiration: C6H12O6 6 O2 --> 6 CO2
cestrela7 [59]

Answer:

O2 is limiting reactant

Explanation:

To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:

<em>Moles C6H12O6:</em>

650g * (1mol/180.16g) = 3.608 moles C6H12O6

<em>Moles O2:</em>

650g * (1mol/32g) = 20.31 moles O2

Now, for a complete reaction of 3.608 moles of C6H12O6 are required:

3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2

As there are just 20.31 moles of O2,

<h3>O2 is limiting reactant</h3>
4 0
3 years ago
Please answer the question circled in red
ki77a [65]

Answer:

i need more info bro

Explanation:

5 0
3 years ago
Read 2 more answers
Electroplating is a way to coat a complex metal object with a very thin (and hence inexpensive) layer of a precious metal, such
8_murik_8 [283]

Answer:

0.0164 g

Explanation:

Let's consider the reduction of silver (I) to silver that occurs in the cathode during the electroplating.

Ag⁺(aq) + 1 e⁻ → Ag(s)

We can establish the following relations.

  • 1 A = 1 C/s
  • The charge of 1 mole of electrons is 96,468 C (Faraday's constant)
  • 1 mole of Ag(s) is deposited when 1 mole of electrons circulate.
  • The molar mass of silver is 107.87 g/mol

The mass of silver deposited when a current of 0.770 A circulates during 19.0 seconds is:

19.0s \times \frac{0.770c}{s} \times \frac{1mole^{-} }{96,468C} \times \frac{1molAg}{1mole^{-}} \times \frac{107.87g}{1molAg} = 0.0164 g

5 0
3 years ago
Other questions:
  • Which acceleration will a 20 Newton force cause if applied to a go kart with a 20 kilogram mass? 1 m/s, 20m/s, 10 m/s, 2 m/s
    9·1 answer
  • Identify the generic outer electron configuration for the akali metals
    11·1 answer
  • Rank the following elements by effective nuclear charge, Zeff, for a valence electron.F LI Be B N
    5·2 answers
  • How many grams of water are needed to react with 44.9 grams of li2o?
    10·1 answer
  • Which of the following statements about the density of the blue object is true?
    12·1 answer
  • The atomic radii of Li, Na, and Rb are 152 pm, 186 pm, and 244 pm, respectively. What is a reasonable estimate for the atomic ra
    15·2 answers
  • 6.Which of the following is NOT true about the lens?
    7·1 answer
  • Question 2
    15·1 answer
  • Use each of the following reaction quotients to write the balanced equation:(b) Q = [NH₃]⁴[O₂]⁷ / [NO₂]⁴[H₂O]⁶
    13·1 answer
  • Rank the substances involved in this reaction in the order of decreasing potential energy:
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!