C. marbles placed inside hollow sphere
Answer:
22.7 g of CaCl₂ are produced in the reaction
Explanation:
This is the reaction:
CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O
Now, let's determine the limiting reactant.
Let's divide the mass between the molar mass, to find out moles of each reactant.
29 g / 100.08 g/m = 0.289 of carbonate
15 g / 36.45 g/m = 0.411 of acid
1 mol of carbonate must react with 2 moles of acid
0.289 moles of carbonate will react with the double of moles (0.578)
I only have 0.411 of HCl, so the acid is the limiting reactant.
Ratio is 2:1, so I will produce the half of moles, of salt.
0.411 / 2 = 0.205 moles of CaCl₂
Mol . molar mass = mass → 0.205 m . 110.98 g/m = 22.7 g
Answer: Hợp chất CTHH 0 °C 10 °C 20 °C 30 °C 40 °C 50 °C 70 °C
Actini(III) hydroxide Ac(OH)3 0,0022
Amonia NH3 1176 900 702 565 428 333 188
Amoni azua NH4N3 16 25,3 37,1
View 42 more rows
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Answer:
2812.6 g of H₂SO₄
Explanation:
From the question given above, the following data were obtained:
Mole of H₂SO₄ = 28.7 moles
Mass of H₂SO₄ =?
Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:
Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)
= 2 + 32 + 64
= 98 g/mol
Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:
Mole of H₂SO₄ = 28.7 moles
Molar mass of H₂SO₄ =
Mass of H₂SO₄ =?
Mole = mass / Molar mass
28.7 = Mass of H₂SO₄ / 98
Cross multiply
Mass of H₂SO₄ = 28.7 × 98
Mass of H₂SO₄ = 2812.6 g
Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄
Explanation:
Are there any values given in the question?
