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Lina20 [59]
2 years ago
5

on their first three plays, the number of yards gained by a football team was -4, -7, and 2. find the total change in yards on t

hese tree plays.​
Mathematics
1 answer:
maria [59]2 years ago
7 0

Answer:

-9

Step-by-step explanation:

The answer is -9 because,

-4 + -7 = -11

Same sign, so you add the numbers and keep the sign.

-11 + 2 = -9

Different signs, subtract the problem. Keep the sign of the BIGGER number.

I hope this helps!

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The number of students at Maria's school decreased by 98% of last year's number currently there are 1170 students how many stude
Vitek1552 [10]
X=number of students at Marita's high school last year
98%=.98
.98x=1170
x=1170/.98
x=1194
3 0
3 years ago
According to rounding rules for addition, the sum of 27.1, 34.538, and 37.68 is ____.
stich3 [128]
We are given with three values and is asked in the problem to determine the sum of the three values. Using a calculator, the significant figures should be equal to 5, the answer is equal to 99.318. One can also use manual addition to verify the answer
5 0
3 years ago
Read 2 more answers
Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon
Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

h(t)=-16t^2+40t+5

we know that

When the ball hits the ground, the height is equal to zero

so

-16t^2+40t+5=0

The formula to solve a quadratic equation of the form

at^{2} +bt+c=0

is equal to

t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+40t+5=0

so

a=-16\\b=40\\c=5

substitute in the formula

t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}

t=\frac{-40\pm\sqrt{1,920}} {-32}

t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec

t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec

therefore

The solution  is t=2.62 seconds

4 0
3 years ago
Find the HCF and LCM of 4x^2 - 36 ,2x^2 - 12x + 18 and 2x^2 + x - 21​
olga_2 [115]

Answer:

(x-3), 4 (x - 3)^2 (x + 3) (2 x + 7)

Step-by-step explanation:

Factor all the expressions,

1st expression= 4x^2 - 36=4(x^2-9)=4(x+3)(x-3)

2nd expression=2x^2 - 12x + 18 =2(x^2-6x+9)=2 (x - 3)^2=2(x-3)(x-3)

3rd expression=2x^2 + x - 21​=(x - 3) (2 x + 7)

HCF=Commo factor=(x-3)

LCF=Common factor*Remaining factor=4(x+3)(x-3)(x-3) (2 x + 7)=4 (x - 3)^2 (x + 3) (2 x + 7)

4 0
3 years ago
Can someone please help me with this
LenKa [72]

Just guess and check. For example, for the first on the left, I guessed 3 to begin with. 3 + 3 + 3 = 9, but 10 + 3 = 13, so 3 is not the answer. I then guessed 5. 5 + 5 + 5= 15, and 10 + 5= 15, so star = 5.

4 0
3 years ago
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