Area of a rectangle of length L and width W is A = LW.
Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.
60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.
Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.
Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.
The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)
Answer:
c. x = -1/15
Step-by-step explanation:
5/2x - 1/3 = -1/2 [multiply the whole equation by 6 (lowest common denom)
15x - 2 = -3 [add 2 on both sides of equation
15x = -1 [divide both sides by 15 to isolate x]
x = -1/15
Answer:
Plug this in a calculator and the answer will pop up.
Step-by-step explanation:
Algebra 1 just really teaches you the basics of algrebra
Answer:
This is quite simple when you consider it. go to -4 on the x axis and find where it goes on the y which in this case is 1. so the output for y is 1
Step-by-step explanation:
