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insens350 [35]
2 years ago
12

Jeffrey and Frank walk at different speeds.Frank’s walking speed can be represented by the equation y=85x, where is the time in

minutes and y is the distance in meters. The distance Jeffrey walked over the time is shown on the graph below

Mathematics
1 answer:
kolezko [41]2 years ago
8 0

Answer:

Option (C)

Option (C)

Option (A)

Step-by-step explanation:

Part A.

Frank's walking speed can be represented by the equation.

Equation representing the speed is,

y = 85x

\frac{y}{x}=85

Therefore, walking speed of Frank = 85 meters per minute.

Option (C) will be the answer.

Part B.

Distance walked over the time by Jeffrey is given by the graph attached.

Equation for the speed will be,

y = (\frac{400}{5})x

y = 80x

Therefore, walking speed of Jeffrey = 80 meters per minute

Difference in the speed of Frank and Jeffrey = 85 - 80 = 5 meters per minute.

Jeffery walks 5 meters per minute slower than Frank.

Option (C) will be the answer.

Part (C)

Distance traveled by Frank in 16 minutes,

y = 85(16) = 1360 meters

Time taken to travel the same distance by Jeffrey will be,

1360 = 80x

x = \frac{1360}{80}=17 meters per minute

Option (A) will be the answer.

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What is the diffrence of 29.22 - 27.54?
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ddd [48]

For this case, we must indicate which of the given graphs corresponds to the following inequality:

y\geq 1-3x

If we substitute the point(x, y) = (0,0) we have:

0> = 1-3 (0)\\0> = 1

It is not met, so we discard options A and C.

It is observed that the lines of option B and D correspond to the equationy = 1-3x. But the dotted line of option B indicates that the region given by: y> 1-3x is plotted

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5 0
3 years ago
1.     At a fundraiser dinner, the bill for 4 cups of coffee
babymother [125]

<u><em>1- Writing the system of equations:</em></u>

The price of a cup of coffee is denoted by c while the price of a spaghetti is denoted by s

<u>We are given that:</u>

4 cups of coffee and 6 spaghetti cost $20.5

<u>This means that:</u>

4c + 6s = 20.5 ................> equation 1

<u>We are also given that:</u>

1 cup of coffee and 3 spaghetti cost $8.75

<u>This means that:</u>

c + 3s = 8.75 .................> equation 2

<em><u>2- Solving the equations using substitution methods:</u></em>

<u>From equation 2:</u>

c = 8.75 - 3s ................> I

<u>Substitute with I in equation 1 and solve for s as follows:</u>

4c + 6s = 20.5

4(8.75 - 3s) + 6s = 20.5

35 - 12s + 6s = 20.5

35 - 6s = 20.5

6s = 14.5

s = $2.41667

<u>Substitute with s in I to get c:</u>

c = 8.75 - 3s

c = 8.75 - 3(2.41667) = 1.4999 = $1.5

<u><em>3- getting price for 1 cup of coffee and 1 spaghetti:</em></u>

c + s = 1.5 + 2.41667 = $3.91667

Hope this helps :)

3 0
2 years ago
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