
Length of each side of each of these three equilateral triangle is :
Solution is in attachment ~
Answer:
B) a = 6.7, B = 36°, C = 49°
Step-by-step explanation:
Fill in the numbers in the Law of Cosines formula to find the value of "a".
a² = b² + c² -2bc·cos(A)
a² = 4² +5² -2(4)(5)cos(95°) ≈ 44.4862
a ≈ √44.4862 ≈ 6.66980
Now, the law of sines is used to find one of the remaining angles. The larger angle will be found from ...
sin(C)/c = sin(A)/a
sin(C) = (c/a)sin(A)
C = arcsin(5/6.6698×sin(95°)) ≈ 48.31°
The third angle is ...
B = 180° -A -C = 180° -95° -48.31° = 36.69°
The closest match to a = 6.7, B = 37°, C = 48° is answer choice B.
Answer:

Step-by-step explanation:
we know that
The formula of slope is "rise over run", where the "rise" (means change in y, up or down) and the "run" (means change in x, left or right)
In this problem
The tangent of angle of 5 degrees is equal to the quotient of "rise over run"
Let
y ----> the rise of the ramp
x ----> the run of the ramp

we have

substitute and solve for x



Answer:
The Scale Factor of the given coordinates is 1/2
I just solved this one
anothe way is undistribute the 2 first and move -14 to side
2(x^2+6x)-14=0
comlete the squer inside and add negative
2(x^2+6x+9-9)-14=0
factor perfect square
2((x+3)^2-9)-14=0
distribute
2(x+3)^2-18-14=0
2(x+3)^2-32=0
add 32 both sides
2(x+3)^2=32
divide 2
(x+3)^2=16
sqrt both sides
x+3=+/-4
minus 3
x=-4-3 or 4-3
x=1 or -7
answer is C