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3 years ago

Solve for x. Round to the nearest tenth, if necessary.

Mathematics

2 answers:

Yakvenalex [24]3 years ago

8 0

X=3.8

Sin41/2.5 = sin90/x
Sin90 x 2.5 = sin41 x X
Sin90 x 2.5/ sin41
X=3.8

Igoryamba3 years ago

5 0

Answer:

3.8106327168

Step-by-step explanation:

x=2.5/sin(41) = 3.81063271676

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Need help pls<br>thank you in advance

ira [324]

Answer:

<u />

$\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}$

$\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10$

$\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10$

<h3><u>Standard Deviation</u></h3>

$\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}$

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's. Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Consider the function f(x) = 20/√x and its second-degree polynomial P2 (x) = 20 - 10(x-1) + 7.5(x-1)^2 at x=0.8. Compute the val

krok68 [10]

Answer:

$f (0.8) = 22.3607$ and $P_{2} (0.8) = 22.300$ .

Step-by-step explanation:

According to the statement, $f (x) = \frac{20}{\sqrt{x}}$ and $P_{2}(x) = 20 - 10 (x-1) + 7.5 (x-1) ^ 2$ . Based on these definitions, at $x=0.8$ produce:

$f (0.8) = \frac{20}{\sqrt {0.8}} = 22.3607$ . On the other hand, you have to:

$P_{2} (0.8) = 20 - 10 (0.8 -1) +7.5 (0.8 -1)^2$

$P_{2} (0.8) = 20 - 10 (-0.2) +7.5 (-0.2)^2 = 22.300$

Then, it can be affirmed that $f (0.8) = 22.3607$ and $P_{2} (0.8) = 22.300$ .

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4 years ago