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Aleks [24]
3 years ago
12

What is the length of the hypothenuse of the triangle?

Mathematics
2 answers:
Artemon [7]3 years ago
6 0

Answer: 26 ft

Step-by-step explanation:

a^2+b^2=c^2

10^2+24^2 = c^2

100+576=c^2

Sqrt 676 = c

C = 26

BlackZzzverrR [31]3 years ago
3 0

Answer:

26ft

Step-by-step explanation:

10^2 +24^2 =AB^2

AB=26

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A flower bed has the shape of a rectangle 5 yards long and 4 yards wide. What is its area in square feet?
aalyn [17]
To find the area, use A= bh (base x height), or A = lw (length x width)

There are 3 feet in 1 yard

3 x 5 = 15
4 x 3 = 12

15 x 12 = 180

The flower bed is 180 ft² 

hope this helps
3 0
3 years ago
Please someone help me
Yuki888 [10]

Answer: H

Step-by-step explanation:

We can see this rectangular prism will have side lengths of 5, 3, 7.

So we can use the fact Surface Area = 2(lh+wh+lw) to get:

2(15 + 35 + 21) = 2(71) = 142

5 0
2 years ago
Write the expressions in standard form. SHOW ALL STEPS! The sum of 9t – 13 and the opposite of 9t.
PSYCHO15rus [73]

Answer:

-13

Step-by-step explanation:

Opposite of 9t = -9t

Taking the sum of 9t - 13 and -9t

Sum = 9t - 13 + (-9t)

Sum = 9t - 13 - 9t

Sum = 9t-9t - 13

Sum  = -13

Hence the expression in standard form is -13

7 0
3 years ago
WILL GIVE BRAINLIEST& 15 PTS.
kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

6 0
3 years ago
Read 2 more answers
I need help so somebody plz help me
Anettt [7]

Answer: A

This is simple. Absolute value inequalities can NOT have a negative. For D, the absolute value is not completely simplified. The negative sign will be removed in the process of solving it.

5 0
3 years ago
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