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maria [59]
2 years ago
6

Complete the table of ordered pairs for the linear y=2x-8

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
8 0

Given:

Consider the below figure attached with this question.

The linear equation is:

y=2x-8

To find:

The values to complete the table of ordered pairs for the given linear equation.

Solution:

We have,

y=2x-8

Substituting x=0 in the given equation, we get

y=2(0)-8

y=0-8

y=-8

So, the value for first blank is -8.

Substituting y=-2 in the given equation, we get

-2=2x-8

-2+8=2x

\dfrac{6}{2}=x

3=x

So, the value for second blank is 3.

Substituting x=2 in the given equation, we get

y=2(2)-8

y=4-8

y=-4

So, the value for third blank is -4.

Therefore, the required complete table is:

     x           y

     0         -8

    3         -2

     2          -4

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Da<br> A<br> Solve the equation 2x^2+3=0
Anika [276]

Answer:

x = ±i(√6 / 2)

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

  • Solving quadratics

<u>Algebra II</u>

Imaginary root i

  • √-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

2x² + 3 = 0

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Subtraction Property of Equality] Subtract 3 on both sides:                        2x² = -3
  2. [Division Property of Equality] Divide 2 on both sides:                                  x² = -3/2
  3. [Equality Property] Square root both sides:                                                    x = ±√(-3/2)
  4. Simplify:                                                                                                             x = ±i(√6 / 2)
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