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2 years ago

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Point C is the center of dilation. Line segment B A is dilated to create line segment B prime A prime. The length of C A is 4. T

he length of A A prime is 16. What is the scale factor of the dilation of line segment BA?

1 answer:

saw5 [17]2 years ago

8 0

Answer:

Step-by-step explanation:

Given

See attachment for figure

$CA = 4$

$CA' = 16$

Required

The scale factor (k)

Since point C is the center of dilation, the scale factor (k) is calculated using:

$k = \frac{CA + CA'}{CA}$

So, we have:

$k = \frac{4+16}{4}$

$k = \frac{20}{4}$

$k = 5$

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adell [148]

Ok, here we go:
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Based off of that we know that car 5 cannot be a convertible since 4 is white and not yellow. So 1 or 2 is the convertible and SUV. But we know that Rachel is in front of a blue car and the yellow car is in front of a convertible so that makes car #2 the blue convertible and car #1 the yellow SUV.

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3 years ago

Which represents r in terms of A and S?

ladessa [460]

Answer:

$r=\frac{6\sqrt{10AS}}{S\sqrt{\pi }}$

Step-by-step explanation:

Given the formula;

$A=\frac{\pi r^2S}{360}$

We want to solve the given formula for r.

Multiply both sides by $\frac{360}{\pi S}$

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$A\times \frac{360}{\pi S}=r^2$

Take square root of both sides

$r=\sqrt{\frac{360A}{\pi S}}$

$r=\frac{\sqrt{360A}}{\sqrt{\pi S}}$

$r=\frac{\sqrt{360A}}{\sqrt{\pi }\sqrt{S}}$

$r=\frac{\sqrt{360A}\times \sqrt{S}}{\sqrt{\pi }\sqrt{S} \times \sqrt{S}}$

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3 years ago

If the circumference is 4.6pi what is the area

Keith_Richards [23]

Answer:

The area of a circle with a circumference of 4.6 is 1.684

Step-by-step explanation:

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3 years ago

Given: triangle ABC,

Andrei [34K]

The value of AD in triangle ABC is approximately 9 cm.

BC = 6cm

Using trigonometric ratio for triangle CBD

sin 60° = opposite / hypotenuse

0.86602540378 = DC / 6

cross multiply

DC = 6 × 0.86602540378

DC = 5.19615242271

DC = 5.20 cm

Let's find side AD as follows:

tan 60° = AD / adjacent

AD = 5.20 × tan 60°

AD = 9.00666419936

AD ≈ 9 cm

learn more: brainly.com/question/10929357?referrer=searchResults

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2 years ago

Read 2 more answers

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nydimaria [60]

Solution: The speed of old freight train is 0.5 miles per minute and the speed of new dart express train is 1.5 miles per minute.

Explanation:

Let the speed of old freight train is x miles per minute and the speed of new dart express train is y miles per minute.

It is given that the speed of the dart express train is three times faster than the freight train. So, it can be written as,

$3x=y$ ....(1)

The trains are moving towards the opposite directions, therefore the distance between them is increased at the speed of $(x+y)$ miles per minute.

$Distance=Speed\times Time$

The distance between both train in 15 minutes is represented by $15(x+y)$ .

According to the given information the distance between trains is 30 miles in 15 minutes.

$15(x+y)=30$

$x+y=2$

Use equation (1) and put $y=3x$

$x+3x=2$

$4x=2$

$x=0.5$

Put this value in equation (1), to find the value of y.

$y=3(0.5)$

$y=1.5$

Therefore, the The speed of old freight train is 0.5 miles per minute and the speed of new dart express train is 1.5 miles per minute.

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3 years ago