Answer:
Its 100!
Step-by-step explanation:
Area of rectangle: 10×8=80
Area of trianagle: Base:10 Height:4
10×4=40
40/2=20
80+20=100!
Hope this helped!
John owns 64.17 percent (rounded to 64%). Sissy owns 34.45 percent (rounded to 34% or 34.5%).
The amount of oxygen in the flask through the intake tube illustrates proportions
The flask 99.35% will contain of oxygen after 5L have passed through the intake tube
<h3>How to calculate the percentage of oxygen?</h3>
To do this, we make use of the following representations
- P for the proportion of oxygen
- V for te volume of oxygen
- x for the proportion of oxygen in the flask after 5 L passed through
So. we have the following derivative
dP = dV - P * dV
Divide through by dV
dP/dV = 1 - P
Next, we set up the integral
![\int\limits^x_{0.040} \frac {1}{1 - P}dP= \int\limits^5_0 {dV}](https://tex.z-dn.net/?f=%5Cint%5Climits%5Ex_%7B0.040%7D%20%20%5Cfrac%20%7B1%7D%7B1%20-%20P%7DdP%3D%20%5Cint%5Climits%5E5_0%20%7BdV%7D)
Integrate both sides
![-\ln(|P - 1|)|\limits^x_{0.04} = 5](https://tex.z-dn.net/?f=-%5Cln%28%7CP%20-%201%7C%29%7C%5Climits%5Ex_%7B0.04%7D%20%3D%205)
Expand
-ln(|x - 1|) + ln(|0.04 - 1|) = 5
Evaluate the difference
-ln(|x - 1|) + ln(|-0.96|) = 5
Express as a fraction
ln(0.96/|x - 1|) = 5
Express both sides as exponents with a base of 2
e^ln(0.96/|x - 1|) = e^5
Solve for x
x = 1 - 0.96/e^5
Evaluate the difference
x = 0.9935
Express as percentage
x = 99.35%
Hence, the flask 99.35% will contain of oxygen after 5L have passed through the intake tube
Read more about proportions at:
brainly.com/question/1781657
3/7
9/28
The second doesn't simplify
Answer:
<em>SR is a secant of circle P</em>
Step-by-step explanation:
see attachment for the missing figure.
In the circle P,
<u>Option A:</u>
N is a point of tangency on circle P.
As Q is a point of tangency of circle P. Therefore, the statement is not true.
<u />
<u>Option B:</u>
PT is a secant of circle P.
As PT is a radius of the circle P. Therefore, the statement is not truee.
<u>Option C:</u>
SR is a secant of circle P.
It is true by the above bulleted points.
<u>Option D:</u>
VU is a tangent of circle P.
As VU is a diameter of the circle P. Therefore, the statement is not true
Therefore, the true statement is <em>SR is a secant of circle P</em>