X^2+6x+8=0
To write the above in the form of (x-p)^2=q we proceed as follows:
i] Re-write the expression:
x^2+6x=-8
ii] Calculate for the vale of c.
c=(b/2a)²
given that:
b=6, and a=1
thus
c=(6/2*1)^2=9
iii]
Add 9 on both sides of the equation from i
x^2+6x+9=-8+9
simplifying we get:
x^2+6x+9=1
factoring the LHS we get:
(x+3)(x+3)=1
(x+3)²=1
The above is in the form of:
(x-p)²=q
where:
p=3 and q=1
Answer:
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Applying the tangent theorem and trigonometry ratio, the measure of angle A is: 19.5°.
<h3>What is the Tangent Theorem?</h3>
The tangent theorem states that if a line is tangent to a circle, the point at which the radius is drawn to the point of tangency is a right angle.
Thus, consider triangle AKO as a right triangle.
Therefore,
- angle A = reference angle
- Ok = 5 (opposite)
- AO = 15 (hypotenuse)
Using the trigonometry ratio, SOH, we have:
sin A = opp/hyp
sin A = 5/15
sin A = 0.3333
A = 19.5°
Therefore, applying the tangent theorem and trigonometry ratio, the measure of angle A is: 19.5°.
Learn more about tangent theorem on:
brainly.com/question/9892082
Answer: p = 1/5
Step-by-step explanation:
-5(p + 3/5) = -4
Now we open the brackets and -5 mutiplies with both terms
-5p - 3 = -4
-5p = -4+3
-5p = -1
p = -1/-5
p = 1/5
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Answer:
6 mhmh
Step-by-step explanation:
