Answer:
a homogeneous mixture of two or more substances
Answer:
Cl⁻
Explanation:
Definition of atomic radii
The atomic radius is the distance between center of two bonded atoms.
Trend along period:
As we move from left to right across the periodic table the number of valance electrons in an atom increase.The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases.
Trend along group:
In group by addition of electron atomic radii increase from top to bottom due to increase in atomic number and addition of extra shell.
In this way Cl⁻ will have the largest atomic radii because one extra electron is added and its atomic number is already greater than fluorine.
1 mole of CO2 has 6.02 x 10^23 molecules of CO2. Say x moles of CO2 has 3.0x10^23 molecules of CO2. Therefore x = 3/6.02 = 0.50. M = 0.50 * (12 + 2x16) = 0.50 * 44 = 22g
An electron has a ( - ) charge and so if an atom gains one electron it gains a - charge
hope that helps
Answer:
Zero order
Explanation:
Looking at the data we can note a linear dependence between concentration and time.
Time Conc.
0 2
15 1.82
30 1.64
48 1.42
75 1.10
In the first 15 min it was consumed 2-1.82=0.18. So the rate is 
From 15 to 30 min (it has passed 15 min) is consumed 1.82-1.64=0.18, so as in the previous calculation the rate is
.
From 30 to 48 (it has passed 18 min)the rate is
From 48 to 75 (it has passed 27 min) the rate is
So these results suggest that despite of the ever minor concentration of the reactant the rate is ever the same. Hence the reaction rate could be expressed as
that is, the reaction is the zero order respect to C2H5I since it is not depending on concentration of C2H5I.