You can use the trigonometric identity
.
The requirement that
eliminates -1/6 from being another solution.
Answer:
<h3>
9, 11, 13, 15</h3>
Step-by-step explanation:
{k - some integer}
2k+1 - the first odd integer (the least)
5(2k+1) - five times the least
5(2k+1)+3 -<u> three more than five times the least</u>
2k+1+2 = 2k+3 - the odd integer consecutive to 2k+1
2k+3+2 = 2k+5 - the next odd consecutive integer (third)
2k+5+2 = 2k+7 - the last odd consecutive integer (fourth)
2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>
2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3
8k + 16 = 10k + 5 + 3
- 10k -10k
-2k + 16 = 8
-16 - 16
-2k = -8
÷(-2) ÷(-2)
k = 4
2k+1 = 2•4+1 = 9
2k+3 = 2•4+3 = 11
2k+5 = 2•4+5 = 13
2k+7 = 2•4+7 = 15
Check: 9+11+13+15 = 48; 48-3 = 45; 45:5 = 9 = 2k+1
Answer:
<u>B. 2</u>
To find MAD, find the mean of the set, then find how far each number is from the mean. Next, find the mean of THAT set of numbers. Yea, I know it's a bit confusing... don't worry!
Find the mean of the set:
12 + 10 + 10 + 8 + 6 + 7 + 7 + 12
72
72 / 8
<u>9</u>
Find how far each number is from 9:
12 - 9 = <u>3</u>
10 - 9 = <u>1</u>
10 - 9 = <u>1</u>
9 - 8 = <u>1</u>
9 - 6 = <u>3</u>
9 - 7 = <u>2</u>
9 - 7 = <u>2</u>
12 - 9 = <u>3</u>
Find the mean of that number set:
{3, 1, 1, 1, 3, 2, 2, 3}
3 + 1 + 1 + 1 + 3 + 2 + 2 + 3
16
16 / 8
<u>2</u>
<u>So the answer is 2!</u>
Not so hard after all :D
Answer:
B, A, C
Step-by-step explanation:
add the like terms together (ending in x2 with x2, ending in x with x etc )
Answer:
x=0
Step-by-step explanation:
Setting f(x)= (x-4)(x+4) = to 0 and solving for x produces the two x-intercepts (not Intersepts) of the function: They are 4 and -4.
The midpoint between these two intercepts is 0.
