So, The dots represent the children.
And the numbers represent the length in.
I wouldnt say its D.
I would say its C. Group B, because 4 kids have forearm length longer then 13 in.
Answer:
D
Step-by-step explanation:
When a function is vertically compressed, this means that the parent function is multiplied by a fraction between 1 and -1. The only answer choice that satisfies this is choice D, meaning that it is the answer. Hope this helps!
Answer:
Step-by-step explanation:
6th term.
a
6
=
32
7th term.
a
7
=
36
t = 5.05 sec
Solution:
Given data:
Initial height
= 24 meter
Initial velocity
= 22 meter
Height of the rock (h) = 10 meter
To find when will the height of the rock be 10 metres:
General formula for the height(meter) of a projectile over time:
![h(t)=-4.9 t^{2}+v_{0} t+h_{0}](https://tex.z-dn.net/?f=h%28t%29%3D-4.9%20t%5E%7B2%7D%2Bv_%7B0%7D%20t%2Bh_%7B0%7D)
Substitute the given data in the above formula.
![10=-4.9 t^{2}+22 t+24](https://tex.z-dn.net/?f=10%3D-4.9%20t%5E%7B2%7D%2B22%20t%2B24)
![-4.9 t^{2}+22 t+24-10=0](https://tex.z-dn.net/?f=-4.9%20t%5E%7B2%7D%2B22%20t%2B24-10%3D0)
![-4.9 t^{2}+22 t+14=0](https://tex.z-dn.net/?f=-4.9%20t%5E%7B2%7D%2B22%20t%2B14%3D0)
This equation looks like a quadratic equation.
We can solve it by using the quadratic formula:
![$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}](https://tex.z-dn.net/?f=%24x%3D%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E%7B2%7D-4%20a%20c%7D%7D%7B2%20a%7D)
Here a = –4.9, b = 22, c = 14
![\begin{aligned}t &=\frac{-22 \pm \sqrt{(22)^{2}-4(-4.9)(14)}}{2(-4.9)} \\&=\frac{-22 \pm \sqrt{484+274.4}}{-9.8} \\&=\frac{-22 \pm \sqrt{758.4}}{-9.8} \\&=\frac{-22 \pm {27.54}}{-9.8} \\t &=\frac{-22-27.54}{-9.8}\ (\text {or})\ t=\frac{-22+27.54}{-9.8}\\t &=5.05\ (\text {or})\ t=-0.56\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Dt%20%26%3D%5Cfrac%7B-22%20%5Cpm%20%5Csqrt%7B%2822%29%5E%7B2%7D-4%28-4.9%29%2814%29%7D%7D%7B2%28-4.9%29%7D%20%5C%5C%26%3D%5Cfrac%7B-22%20%5Cpm%20%5Csqrt%7B484%2B274.4%7D%7D%7B-9.8%7D%20%5C%5C%26%3D%5Cfrac%7B-22%20%5Cpm%20%5Csqrt%7B758.4%7D%7D%7B-9.8%7D%20%5C%5C%26%3D%5Cfrac%7B-22%20%5Cpm%20%7B27.54%7D%7D%7B-9.8%7D%20%5C%5Ct%20%26%3D%5Cfrac%7B-22-27.54%7D%7B-9.8%7D%5C%20%28%5Ctext%20%7Bor%7D%29%5C%20%20t%3D%5Cfrac%7B-22%2B27.54%7D%7B-9.8%7D%5C%5Ct%20%26%3D5.05%5C%20%28%5Ctext%20%7Bor%7D%29%5C%20%20t%3D-0.56%5Cend%7Baligned%7D)
Time cannot be indicated in negative. So neglect t = –0.56.
Therefore, t = 5.05 sec
Hence after 5.05 sec the rock will be 10 meters from ground level.