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Lynna [10]
3 years ago
9

Jon is hanging a picture. He wants to center it horizontally on the wall. The picture is 32 1/2 inches long, and the wall is 120

3/4 inches long. How far from each edge of the wall should he place the picture? Please answer quickly.
Mathematics
1 answer:
frozen [14]3 years ago
8 0

Answer:

44.125 inches

Step-by-step explanation:

Given that:

Length of picture = 32 1/2 inches

Length of wall = 120 3/4 inches

Hence, to center picture horizontally ;

Distance from the edge of the wall in which the picture should be placed :

(Length of wall - length of picture) / 2

(120 3/4 - 32 1/2) / 2

(483/4 - 65/2) / 2

Take the L. C. M of 4 and 2 = 4

((483 - 130) / 4) ÷ 2

(353 / 4) ÷ 2

(353 / 4) * (1 / 2)

= 353 / 8

= 44 1/8

= 44 1/8

= 44.125 inches

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The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​
Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is \dfrac{15}{2}.

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The sum of first six terms.​

Solution:

We have,

S_2=6

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S_n=\dfrac{a(1-r^n)}{1-r}              ...(i)

Putting n=2, we get

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S_4=\dfrac{a(1-r^4)}{1-r}

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Case 2: If r is negative, then using (ii) we get

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S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}

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