Answer:
$82 sundaes
$74 banana split
Step-by-step explanation:
Step one :
Given data
Cost of sundaes =$2 each
Cost of banana split =$3 each
Let the number of sundaes bought be x
And the number of banana split bought be y
The total is x+y
The shop sold 8 more Sundaes than the Banana split
x=8+y—-------1
Total amount made = $156
Therefore the system of equation for the situation is
x=8+y----—----------1
2x+3y=156---------2
But x=8+y
8+y+y=156
8+2y=156
2y=156-8
2y=148
Divide both sides by 2
y=148/2
y=74
On That day they sold $74 banana split
And also they sold x=8+74=$82 sundaes
<u><em>Answer:</em></u>
24.2%
<u><em>Explanation:</em></u>
<u>The percentage of people choosing strawberry can be calculated as follows:</u>
<u>We have:</u>
Number of people choosing strawberry = 15 people
Total number of surveyed people = 17 + 10 + 17 + 3 + 15 = 62 people
<u>Substitute in the above rule to get the percentage as follows:</u>
%
Hope this helps :)
Answer:
Area of triangle RST = 95 in² (Approx)
Step-by-step explanation:
Given:
Side a = 22 in
Side b = 13 in
Perimeter = 50 in
Find:
Area of triangle
Computation:
Side c = Perimeter - Side a - Side b
Side c = 50 - 22 - 13
Side c = 15 in
Heron's formula:
s = Perimeter / 2 = 50 / 2
s = 25 in
Area of triangle = √s(s-a)(s-b)(s-c)
Area of triangle = √25(25-22)(25-12)(25-15)
Area of triangle = √25(3)(13)(10)
Area of triangle = 5√390
Area of triangle = 5 × 19(approx)
Area of triangle RST = 95 in² (Approx)
Answer:
p = ½ (x₁ + x₂)
q = a (x₁x₂ − ¼ (x₁ + x₂)²)
Step-by-step explanation:
y = a (x − x₁) (x − x₂)
Expand:
y = a (x² − x₁x − x₂x + x₁x₂)
y = a (x² − (x₁ + x₂)x + x₁x₂)
Distribute a to the first two terms:
y = a (x² − (x₁ + x₂)x) + ax₁x₂
Complete the square:
y = a (x² − (x₁ + x₂)x + ¼(x₁ + x₂)²) + ax₁x₂ − ¼ a(x₁ + x₂)²
y = a (x − ½ (x₁ + x₂))² + a (x₁x₂ − ¼ (x₁ + x₂)²)
Therefore:
p = ½ (x₁ + x₂)
q = a (x₁x₂ − ¼ (x₁ + x₂)²)
Answer:
The Answer is C
Step-by-step explanation:
3x-4y=5
2x+4y=-3
This equation is the answer to this problem because just by looking at it, you can immediately cancel out the y value and solve for x.
The other equations are wrong because their is extra work needed to eliminate the values.
