Answer:
A. (0, 5)
Step-by-step explanation:
Physically speaking, the volume of the box and the side of the square cutout are positive value. So that the following inequations must be satisfied:
(1)
(2)
(3)
From (1), (2), (3) we find that:
(1):

(2):



(3):



We see that equation above is the multiplication of a first grade monomial and two first grade binomials, which means that:


In other words, the reasonable domain for this situation is A.
The sample space will be: {1, 2, 3, 4, 5, 6}
Event A is: {Rolling 1,2 or 3}
Complement of event A will contain all those outcomes in the sample space which are not a part of event A.
So, complement of event A will be: {Rolling a 4,5 or 6}
Thus option A gives the correct answer
The answer is 8. Anything else?