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Schach [20]
3 years ago
15

In triangles ABC and WXY, a=w and b=x

Mathematics
1 answer:
allsm [11]3 years ago
4 0

Answer:

C. AB = WX

Step-by-step explanation:

We are given,

Triangles ABC and WXY having ∠A=∠W and ∠B=∠X

Now, it is give that the triangles hold AAS theorem.

Since, we already have two corresponding angles equal i.e. ∠A=∠W and ∠B=∠X.

So, by AAS Theorem, the corresponding sides between these angles must be  equal.

Thus, we have, AB = WX.

Hence, option C is correct.

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Graph the line with slope -3 passing through the point (3,-4)
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Given: \textsf{Slope = -3, Passes through (3, -4)}

Find:  \textsf{Equation in slope-intercept form}

Solution: The first step that we need to take is to plug the given values into the point-slope formula which would help us out since we have both the slope and a point.  Using that we would then distribute on the right side of the expression and then subtract 4 from both sides which would isolate y.

<u>Plug in the values</u>

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<u>Distribute</u>

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Therefore, after plugging in the values and completing the rest of the steps we were able to determine that equation of the data provided would be y = -3x + 5.

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Read 2 more answers
What is the simplified form of the expression? k^3{k^7/5}^-5
Fantom [35]

Answer: B

k^-4= 1 / k^4

Step-by-step explanation:

The expression is

k^3{k^7/5}^-5

To simplify the expression, we take the following steps.

Recall the following laws of indices

a^x + a ^y = a ^ (x+y) - - - - - - - - - -1

(a^x)^y = a^(x×y) = a^ xy - - - - - - - 2

a ^-x = 1 / a^ x - - - - - - - - - - - - - - - 3

Applying these laws of indices, we have

k^3{k^7/5}^-5

(applying law 2), we have

= k^3{k^7/5× -5}

= {k^3{k^7×-1} = {k^3{k^-7}

(applying law 1 )

k^3(k^-7) = k^ (3+ -7) = k ^3-7 = k^-4

Applying law 3,

k^-4= 1 / k^4

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