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3 years ago

In the compound Ni2O3, nickel's oxidation number is_____

Chemistry

1 answer:

zimovet [89]3 years ago

8 0

Answer:

Explanation:

The name of this compound would be nickel (III) oxide. Oxygen typically has a charge of -2. Given there are 3 oxygen atoms, that would equal a charge of -6. The nickel is the cation and must equal the charge of the anion, so must have a charge of +6. Since there are 2 nickel atoms, the charge on each must be +3.

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Select the name of the element with a condensed ground-state electron configuration of [kr] 5s14d7.

Vilka [71]

elements have equal number of protons and neutrons

the condensed format is when the closest noble gas with the closest electron configuration is given, this closest noble gas atomic number should be lesser than the atoms atomic number

atomic number of Kr is 36

1 electron in 5s subshell and 7 electrons in 4d subshell.

there's a total of 36 + 1 + 7 = 44 electrons

atomic number of the atom is 44

element with atomic number 44 is Ruthenium - Ru

answer is Ru

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antiseptic1488 [7]

Electronegativity of the two atoms is your answer

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4 years ago

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Which process takes place when recharging a rechargeable battery?

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Moving of positive charge electron and negative charge proton.

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4 years ago

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Which of the following statements are NOT true:(you can pick more then one)

Evgesh-ka [11]

The answer is B!!! Statement B is not true!

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3 years ago

cooling a sample of matter from 70°c to 10°c at constant pressure causes its volume to decrease from 873.6 to 712.6 cm3. classif

jek_recluse [69]

Explanation:

Expression for the coefficient of thermal expansion is as follows.

$\alpha = \frac{1}{V}(\frac{\Delta V}{\Delta T})$

where, V = initial volume

$\Delta V$ = Final volume - initial volume

= (712.6 - 873.6) $cm^{3}$

= -161 $cm^{3}$

Now, we will calculate the change in temperature as follows.

$\Delta T$ = Final temperature - Initial temperature

= (10 + 273) K - (70 + 273) K

= 283 K - 343 K

= -60 K

Substituting these values into the equation as follows.

$\alpha = \frac{1}{873.6} \times (\frac{161}{60}) K^{-1}$

= 0.00307 $K^{-1}$

It is known that for non-ideal gases the value of alpha is 0.366% which is 0.00366 per Kelvin. As it is close to our result, hence the given sample of gas is a non-ideal gas.

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4 years ago