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4 years ago

Calculate these masses.

2 answers:

Alex4 years ago

8 0

A) mass / volume = density
m/6.00cm3 = 13.5939g/cm3
m = 13.5939g/cm3 • 6.00cm3
m = 81.6g

B) mass / volume = density
m/25.0cm3 = 0.702g/cm3
m = 0.702cm3 • 25.0g/cm3
m = 17.6g

1mL = 1cm3

RUDIKE [14]4 years ago

6 0

Answer:

(a) $m = 81.6g$

(b) $m = 17.6g$

Explanation:

Hello,

In this case, we consider the formula of density and solve for the required mass in each statement:

$\rho =\frac{m}{V} \\m=\rho *V$

In such a way we compute them as:

(a) $m=6.00cm^3*13.5939g/cm^3=81.6g$

(b) $m=25.0 mL*\frac{1cm^3}{1mL}*0.702g/cm^3 =17.6g$

Best regards.

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We are given:

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By Stoichiometry of the reaction:

If 23.4 kJ of heat is released, then 1 mole of magnesium carbonate is dissolved

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To calculate the mass of the substance by given number of moles, we use the equation:

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Moles of magnesium carbonate = 0.083 moles

Molar mass of magnesium carbonate = 84.3 g/mol

Putting values in above equation, we get:

$0.083mol=\frac{\text{Mass of magnesium carbonate}}{84.3g/mol}\\\\\text{Mass of magnesium carbonate}=0.083mol\times 84.3g/mol=6.99g$

Hence, the mass of magnesium carbonate that will be dissolved in the reaction is 6.99 g.

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4 years ago

A sucrose solution is prepared to a final concentration of 0.210 MM . Convert this value into terms of g/Lg/L, molality, and mas

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1) 71.9 g/L

2) 0.221 m olal

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Explanation:

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Suppose we have a volume of 1.00L

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Step 2: Calculate molality

Molality = moles sucrose / mass water

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