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4 years ago

Calculate these masses.

2 answers:

Alex4 years ago

8 0

A) mass / volume = density
m/6.00cm3 = 13.5939g/cm3
m = 13.5939g/cm3 • 6.00cm3
m = 81.6g

B) mass / volume = density
m/25.0cm3 = 0.702g/cm3
m = 0.702cm3 • 25.0g/cm3
m = 17.6g

1mL = 1cm3

RUDIKE [14]4 years ago

6 0

Answer:

(a) $m = 81.6g$

(b) $m = 17.6g$

Explanation:

Hello,

In this case, we consider the formula of density and solve for the required mass in each statement:

$\rho =\frac{m}{V} \\m=\rho *V$

In such a way we compute them as:

(a) $m=6.00cm^3*13.5939g/cm^3=81.6g$

(b) $m=25.0 mL*\frac{1cm^3}{1mL}*0.702g/cm^3 =17.6g$

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3 years ago

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Answer:

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B) M = 36X

C) M = 178.88X

Explanation:

Given data:

ASTM grain size number 7

a) total grain per inch^2 - 64 grain/inch^2

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therefore we have

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B) total grain per inch^2 = 500 grain/inch^2

we know that number of grain per square inch is given as

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where M is magnification, n is grain size

therefore we have $500 = 2^{7-1}(\frac{100}{M})^2$

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we know that number of grain per square inch is given as

$Nm = 2^{n-1} (\frac{100}{M})^2$

where M is magnification, n is grain size

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The partial pressure of cartbon dioxide in the atmgsphere is 0239 toer Caiculate the partial pressure in mm He and atm Rpund eac

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Answer :

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As, $1torr=1mmHg$

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