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RUDIKE [14]
3 years ago
7

When does the dipole arrow point to Atom A? (Use electronegativity in your explanation)

Chemistry
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

Dipole, less electronegativity,  higher electronegativity

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Chromium (III) forms a complex with diphenylcarbazide whose molar absorptivity is 4.17x104 at 540 nm.
son4ous [18]

Answer:

3.00 cm

Explanation:

The absorbance can be expressed using <em>Beer-Lambert's law</em>:

A = ε*b*c

Where ε is a constant for each compound, b is the optical path, and c is the molar concentration of the compound.

Now we <u>match the absorbance values for both solutions</u>, because we want the absorbance value to be the same for both solutions:

A = ε * 1.00 cm * 7.68x10⁻⁶M = ε * b * 2.56x10⁻⁶ M

And <u>solve for b:</u>

 ε * 1.00 cm * 7.68x10⁻⁶M = ε * b * 2.56x10⁻⁶ M

1.00 cm * 7.68x10⁻⁶M = b * 2.56x10⁻⁶ M

b = 3.00 cm

5 0
3 years ago
Which option is a physical property of matter?
Elan Coil [88]

Answer:

boiling point is the physial property of matter

5 0
3 years ago
Which diagram represents a physical change,only?
Lorico [155]
There is no diagram
8 0
3 years ago
Write equations for the half-reactions that occur at the anode and cathode for the electrolysis of each of the following aqueous
nirvana33 [79]
For NaBr(aq) hydrogen gas is formed at the cathode. Hydrogen in water is reduced to hydrogen gas. For NaBr(aq), bromine, Br2(l), will be produced instead of oxygen gas at the anode. 

<span>For sodium sulfate hydrogen gas is formed at the cathode. Hydrogen in water is reduced to hydrogen gas. Oxygen gas will be produced at the anode. </span>

<span>Should someone suggest that sodium metal is formed at the cathode, rest assured that that can't happen. Sodium metal reacts with water to make Na+. </span>

<span>Lead(II) iodide is insoluble in water. Therefore, not much will happen since there is no electrolyte.</span>
7 0
3 years ago
If the specific heat of water is 4.18 3/g*^ C much heat is required to increase the temperature of 12 g of water from 23 degrees
12345 [234]

Answer:

Q = 802.6 J

Explanation:

Given data:

Specific heat capacity of water = 4.18 J/g.°C

Mass of water = 12 g

Initial temperature = 23°C

Final temperature = 39°C

Heat required = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 39°C - 23°C

ΔT = 16 °C

Q = 12 g× 4.18 J/g.°C × 16 °C

Q = 802.6 J

3 0
3 years ago
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