Left Panel
A is an acid. Not the answer.
B is correct. That would be a base. But it is not an Arrhenius base. Keep reading.
C that is exactly what an Arrhenius base is.
D. No an acid of some sort would accept OH ions.
Right Panel
D is concentrated and it is also a weak base. Good cleaning fluid. Smells awful but it works.
Answer:
47, 68, 47
Explanation:
Let's consider the following isotope: ¹¹⁵Ag.
If we look in the Periodic Table, the atomic number of Ag is 47, that is, silver has 47 protons.
Since ¹¹⁵Ag is neutral it must have the same number of protons that of electrons. Then, it also has 47 electrons.
The number 115 in ¹¹⁵Ag stands for the mass number, which is the sum of protons and neutrons. Then, the number of neutrons is:
p⁺ + n⁰ = 115
n⁰ = 115 - p⁺ = 115 - 47 = 68
The number of protons, neutrons, and electrons in ¹¹⁵Ag is: 47, 68, 47.
Hey there!
density = 2.67 g/cm³
mass = 1340 g
volume = ?
Therefore:
D = m / V
2.67 = 1340 / V
V = 1340 / 2.67
V = 501.87 cm³
Answer:
43.2 moles of carbon dioxide are required and 421g of glucose could be produced
Explanation:
Based on the reaction:
6CO2 + 6H2O → C6H12O6 + 6O2
1 mole of glucose, C6H12O6, requires 6 moles of carbon dioxide. 7.2moles of glucose requires:
7.2mol C6H12O6 * (6mol CO2 / 1mol C6H12O6) =
<h3>43.2 moles of carbon dioxide are required</h3><h3 />
618g of CO2 -Molar mass: 44.01g/mol- are:
618g * (1mol / 44.01g) = 14.04moles CO2
Moles C6H12O6:
14.04moles CO2 * (1mol C6H12O6 / 6mol CO2) = 2.34moles C6H12O6
Mass glucose -Molar mass: 180.156g/mol-
2.34moles C6H12O6 * (180.156g / mol) =
<h3>421g of glucose could be produced</h3>
