Mr. Jansen opend a savings account with an initial deposit of $720 and will not make any additional deposits or withdrawals. The
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In short, (h o g)(a) is just h( g(a) ).
so what we can do is simply get g(a) first and then plug that in h(x).
so what we can do is simply get g(a) first and then plug that in h(x).
The correct choice of this question with the given polynomial is <em>"The zeros are </em>-2<em> and </em>8<em>, because the factors of g are (x + </em>2<em>) and (x - </em>8<em>)"</em>. (Correct choice: H)
<h3>How to analyze a second orden polynomial with constant coefficients</h3>
In this case we have a second order polynomial of the form <em>x² - (r₁ + r₂) · x + r₁ · r₂</em>, whose solution is <em>(x - r₁) · (x - r₂)</em> and where <em>r₁</em> and <em>r₂</em> are the roots of the polynomial, which can be real or complex numbers but never both according the fundamental theorem of algebra.
If we know that <em>g(x) =</em> <em>x² -</em> 6 <em>· x -</em> 16, then the <em>factored</em> form of the expression is <em>g(x) = (x - </em>8<em>) · (x + </em>2<em>)</em>. Hence, the correct choice of this question with the given polynomial is <em>"The zeros are </em>-2<em> and </em>8<em>, because the factors of g are (x + </em>2<em>) and (x - </em>8<em>)"</em>.
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