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3 years ago

6

The relationships for Paul's and Steve's height with respect to Theresa's height are described above. First you will write expre

ssions for Paul's height and for Steve's height. Then you will relate the expressions.

2 answers:

Varvara68 [4.7K]3 years ago

7 0

Answer:

Theresa’s height is t inches. Paul says he is 16 inches shorter than 1 1/2 times Theresa’s height.

Paul's height in inches

= 1 1/2⁢t−16

= 3/2⁢t−16

The expression that represents Paul’s height in inches is 3/2t−16.

Theresa’s height is t inches. Steve says he is 6 inches shorter than 1 1/3 times Theresa’s height.

Paul's height in inches

= 1 1/3⁢t−6

= 4/3t−6

The expression that represents Steve’s height in inches is 4/3⁢t−6.

Step-by-step explanation:

Makovka662 [10]3 years ago

5 0

Answer:

They are tall, im not sure

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How many real solutions does the equation y2− 8y + 16 = 0 have?

saveliy_v [14]

We can solve this equation by completing the square. Notice that $4*2=8$ and $4^{2}=16$ . Therefore, we can turn $y^{2}-8y+16=0$ into $(y-4)^{2}=0$ . y, in this equation, only has one real solution: 4. So your answer would be (B).

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3 years ago

out of 1200 student served at lunch 660 of the students get hamburgers what is the percent of people who got hamburgers

Mars2501 [29]

Answer:

45% of students got hamburgers :)

Step-by-step explanation:

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3 years ago

The number of responses to a survey are shown in the Pareto chart. The survey asked 1052 adults how they would grade the quality

Goryan [66]

Answer: (a) P(no A) = 0.935

(b) P(A and B and C) = 0.0005

(c) P(D or F) = 0.379

(d) P(A or B) = 0.31

Step-by-step explanation: <u>Pareto</u> <u>Chart</u> demonstrates a relationship between two quantities, in a way that a relative change in one results in a change in the other.

The Pareto chart below shows the number of people and which category they qualified each public school.

(a) The probability of a person not giving an A is the difference between total probability (1) and probability of giving an A:

P(no A) = $1-\frac{68}{1052}$

P(no A) = 1 - 0.065

P(no A) = 0.935

b) Probability of a grade better than D, is the product of the probabilities of an A, an B and an C:

P(A and B and C) = $(\frac{68}{1052})(\frac{258}{1052})(\frac{327}{1052})$

P(A and B and C) = $\frac{5736888}{1164252608}$

P(A and B and C) = 0.0005

c) Probability of an D or an F is the sum of probabilities of an D and of an F:

P(D or F) = $\frac{269}{1052} +\frac{130}{1052}$

P(D or F) = $\frac{399}{1052}$

P(D or F) = 0.379

d) Probability of an A or B is also the sum of probabilities of an A and of an B:

P(A or B) = $\frac{68}{1052} +\frac{258}{1052}$

P(A or B) = $\frac{326}{1052}$

P(A or B) = 0.31

7 0

3 years ago

The total length of wires a b and c is 445 cm wire a is 45 cm longer then wire b and wire b is half as long as wire c how long i

Oksana_A [137]

Answer:

$a = 145\ cm$

Step-by-step explanation:

Given

$a + b + c = 445$

$a = 45 + b$

$b = \frac{1}{2}c$

Required

Determine the length of a

Solve for c in $b = \frac{1}{2}c$

$2 * b = \frac{1}{2}c * 2$

$2b = c$

$c = 2b$

Substitute $c = 2b$ and $a = 45 + b$ in $a + b + c = 445$

$a + b + c = 445$

$45 + b + b + 2b = 445$

$45 + 4b = 445$

Solve for 4b

$4b = 445 - 45$

$4b = 400$

Solve for b

$b = 400/4$

$b = 100$

Recall that: $a = 45 + b$

$a=45+100$

$a = 145\ cm$

6 0

3 years ago

A colony contains 1500 bacteria. The population increases at a rate of 115% each hour. If x represents the number of hours elaps

Burka [1]

Answer:Answer:

Option (c) is correct.

function representing the increase of bacteria every hour x,

Step-by-step explanation:

Given : A colony contains 1500 bacteria. The population increases at a rate of 115% each hour.

we have to find the function that represents the given scenario.

Let x represents the number of hours elapsed.

Given A colony contains 1500 bacteria

and number of bacteria is increasing at a rate of 115% each hour.

Using formula for Compound interest , we have,

Where A is amount

T is time period

R is rate of interest

Here, P = 1500

T = x hours

R = 115%

Let f(x) be the function representing the increase of bacteria every hour.

Substitute, we have,

Simplify, we get,

Thus, function representing the increase of bacteria every hour x,

5 0

3 years ago