How do you find the oxidation number on an atom

Which of the following is a proton donor. a. Bronsted-Lowry Base 6 Bronsted-Lowry Acid c. Lewis Acid d. Lewis Base

Margarita [4]

Answer:

Bronsted-Lowry acid

Explanation:

Bronsted-Lowry Base -

According to Bronsted-Lowry theory of acids and bases:

Acids are those substances which donate proton in the solution whereas bases are those substances which accept proton in the solution.

Consider an example,

$HCO_3^{-} + HOH\; \rightarrow H_2CO_3 + OH^{-}\\$

HCO3- behave as base as it accepts proton in the reaction whereas HOH behaves as acid as it releases proton.

According to Lewis theory of acids and bases:

Acids are electron acceptor and bases are electron donar. Acids are generally electron deficient species whereas Lewis are chemical species having lone pair of electrons.

For example, AlCl3 is behave as Lewis acid because of being electron deficient species.

NH3 is a Lewis base because of presence of lone pair of electrons.

Therefore, among given options, Bronsted-Lowry acid is the correct option.

3 0

4 years ago

Which of the following is true about the speed of light? (2 points)<br><br> Group of answer choices

riadik2000 [5.3K]

Answer:

Speed of light is measured in vacuum and is equal to 671 million miles per hour, 1080 million kilometers per hour, 173 astronomical meters per second.

The exact value of speed of light is considered to total 299,792,458 meters per second

6 0

4 years ago

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Calculate the change in energy when 75.0 grams of water drops from<br> 31.0C to 21.6.

zysi [14]

Answer: Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

oC

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

o

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

5 0

4 years ago

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A chemist heats a fixed amount of gas in a sealed glass container. Which law is the chemist most likely

Hitman42 [59]

It’s gay-lussacs law by seeing how changes in tenet arise affect the volume of gas I think

7 0

3 years ago

Chewing sugar-free gum can help stimulate the production of _______ in the mouth

Ne4ueva [31]

Answer:

chewing sugar-free gum can help stimulate the production of damage

4 0

4 years ago

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