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3 years ago

water droplets tend to have a spherical, round shape, Explain ths fact in terms of the polar nature of water molecules

1 answer:

6 0

What does it happen in smallest scale?
You have to look for "DUPRE' EQUATION" which treat about 
"TWO-PHASE INTERFACIAL FORCEs". 
At boundary surface between two aggregation phases, you may attribute upper energy level to molecules standing at the boundary zone. So, it has to define INTERFACIAL FORCEs WHICH ACT TO REMODEL SHAPE AND EXTENSION OF MEETING PHASEs. 
In your case, Water's Droplet is a liquid phase surrounded by Air (e.g. gas phase) and Interfacial Forces act to dominate Boundary-Surface. 
Mathematically, smallest possible Surface comes to SPHERICAL SHAPE.

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A log burns to ashes in a fireplace what kind of change is this

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The density of solid aluminum is 2.70 . If a 1g peice of aluminum is dropped in a cup of water, it will . (The density of water

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It will sink

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3 years ago

Energy in the amount of 420 J is added to a 35 g sample of water at a temperature of 10°C. What is the final temperature of the

Vsevolod [243]

The final temperature of the water, T2 = 38.57°C

Temperature can be defined as a measure of the degree of hotness or coldness of a physical object (body). Thus, it is measured with a thermometer and its units are degree Celsius (°C), Fahrenheit (°F) and Kelvin (°K).

A calorie refers to the amount of heat required to raise the temperature of a gram of water by one (1) degree Celsius (1°C).

Given the following data:

Quantity of energy = 420J

Mass = 35 grams

Initial temperature, T1 = 10°C

The specific heat capacity of water is 4.2 J/g°C.

To find the final temperature of the water (T2):

Mathematically, the quantity of energy (heat capacity) is given by the formula;

$Q = mcdt$

Where;

Q represents the heat capacity or quantity of heat.

M represents the mass of an object.

C represents the specific heat capacity of water.

dt represents the change in temperature.

Substituting the values into the formula, we have;

$420 = 3.5 \; * \; 4.2 \; * \; dt$

$420 = 14.7 \; * \; dt\\\\dt = \frac{420}{14.7}$

Change in temperature, dt = 28.57°C

Next, we would solve for the final temperature by using this formula;

$dt = T2 - T1$

$28.57 = T_{2} - 10\\\\T_{2} = 28.57 \; + \; 10\\\\T_{2} = 38.57$

Final temperature, T2 = 38.57°C

Therefore, the final temperature of the water, T2 is equal to 38.57°C

For more information visit: brainly.com/question/22736508

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3 years ago

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