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3 years ago

Nonmetallic elements form ions by _____ valence electrons to complete their outer shell.

Chemistry

1 answer:

Brums [2.3K]3 years ago

7 0

Answer: Non-metals form ions when they gain electrons.

Explanation:

An ion is formed when an atom looses or gains electron.

When an atom looses electrons, it will form a positive ion known as cation.
When an atom gains electrons, it will form a negative ion known as anion.

Metals are the elements which have a tendency to loose electrons and thus they form cations. Example: Sodium will loose 1 electron to form $Na^+$ ion.

Non-metals are the elements which have a tendency to gain electrons and thus they form anions. Example: Fluorine will gain 1 electron to form $F^-$ ion.

Hence, non-metals form ions when they gain electrons.

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Consider the balanced equation for the following reaction:

Zanzabum

Answer: The amount of carbon dioxide formed in the reaction is 5.663 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of oxygen gas = 8 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{8g}{32g/mol}=0.25mol$

For the given chemical equation:

$7O_2(g)+2C_2H_6(g)\rightarrow 4CO_2(g)+6H_2O(l)$

By Stoichiometry of the reaction:

7 moles of oxygen gas produces 4 moles of carbon dioxide

So, 0.25 moles of oxygen gas will produce = $\frac{4}{7}\times 0.25=0.143mol$ of carbon dioxide

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 0.143 moles

Putting values in equation 1, we get:

$0.143mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(0.143mol\times 44g/mol)=6.292g$

To calculate the experimental yield of carbon dioxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Percentage yield of carbon dioxide = 90 %

Theoretical yield of carbon dioxide = 6.292 g

Putting values in above equation, we get:

$90=\frac{\text{Experimental yield of carbon dioxide}}{6.292g}\times 100\\\\\text{Experimental yield of carbon dioxide}=\frac{90\times 6.292}{100}=5.663g$

Hence, the amount of carbon dioxide formed in the reaction is 5.663 grams

7 0

3 years ago

A 25.0 g block of a metal alloy at 100 C is dropped into an insulated flask containing 110 g of ice; 5.30 g of the ice melted. W

mr_godi [17]

Answer:

0.00353J/g/°C

Explanation:

I will assume the temperature of the ice to be approximately 0°C.

Moreover, Heat of fusion of water is 6kJ

Amount of heat used to melt 5.3g of ice = 5.3 x 6 / 18

=1.767g°C

Therefore

1.767 = 25 x specific heat cap. x 200

Specific heat cap. = 1.767/(25x200)

= 0.00353J/g/°C

6 0

3 years ago

Identify all statements that accurately describe the structure of the pyruvate dehydrogenase ( PDH ) complex.

Nostrana [21]

Answer:

The statements that correctly describes pyruvate dehydrogenase includes:

- Several copies each of E 1 and E 3 surround E 2.

-A regulatory kinase and phosphatase are part of the mammalian PDH complex.

-E 2 contains three domains.

Explanation:

Pyruvate dehydrogenase is a hydrolase key enzyme in glucose metabolism which converts pyruvate to acetyl- ChoA. It also forms a complex that catalyzes an irreversible reaction that is the entry point of pyruvate into the TCA cycle. Pyruvate dehydrogenase complex contains E1, E2 and E3 enzymes that transform pyruvate, NAD+, coenzyme A into acetyl-CoA, CO2, and NADH. Also, A regulatory kinase and phosphatase are part of the mammalian PDH complex and E 2 contains three domains.

5 0

3 years ago

What is the name of the compound BrF

Rashid [163]

Bromine

hope that helps :)

7 0

2 years ago

Read 2 more answers

A mixture of gases contains 4.46 moles of neon (Ne), 0.74 mole of argon (Ar), and 2.15 moles of xenon (Xe). Calculate the partia

viva [34]

Explanation:

The partial pressure of an individual gas is equal to the total pressure of the mixture multiplied by the mole fraction of the gas.

Total pressure = 2atm

Mole Fraction = number of moles / total number of moles

Neon

Mole Fraction = 4.46 / 7.35 = 0.607

Partial Pressure = 0.607 * 2 = 1.214 atm

Argon

Mole Fraction = 0.74 / 7.35 = 0.101

Partial Pressure = 0.101 * 2 = 0.202 atm

Xenon

Mole Fraction = 2.15 / 7.35 = 0.293

Partial Pressure = 0.293 * 2 = 0.586 atm

5 0

3 years ago