Answer:
Concentration of KOH = 1.154 M
Explanation:
In the above reaction, 1 mole of oxalic acid reacts with 2 moles of KOH.
Mass of oxalic acid = 0.604 g
Molecular mass of oxalic acid = 90.03 g/mol
1 mol of oxalic acid reacts with 2 moles of KOH
0.0067 mol of oxalic acid reacts with 
Volume of the solution = 27.02 mL = 0.0272 L
No. of mole of KOH = 0.0134 mol
Concentration of KOH = 1.154 M
Answer:
3-³ x (1/3)^-5 x (1/3)-²
Applying Indices
3^-3 x (3-¹)^-5 x (3-¹)^-2
When the negative signs interact
they become positive
We now have
3^-3 x 3^5 x 3^2
= 3^-3 x 3^7
=3⁴.
Answer:
far apart
Explanation:
The molecules of any gaseous compounds are loosely bound and the molecules are far apart from each other. They move freely and rapidly. The inter-molecular forces are lower as compared to a solid or a liquid where the molecules are comparatively closely bound in the compounds.
Because of the large gap or distance between its molecules, gaseous compounds have less density when compared to any solid or liquid.
Atomic <span>mass He = 4.002 u.m.a
4.002 g --------------- 6.02x10</span>²³ atoms
50 g ------------------ ? atoms
50 x ( 6.02x10²³) / 4.002
= 3.01x10²⁵ / 4.002
= 7.52x10²⁴ atoms of He
D. The total number of gas molecules will decrease.
Explanation:
According to Le Chatelier's principle, an increase in pressure in a system involving gases will cause the total number of gas molecules to decrease.
Le Chatelier's principle states that "if any conditions of a system in equilibrium is changed, the system will adjust itself in order to annul the effect of the change".
In a reaction involving gases, a change in pressure affects only reactions in a gaseous phase.
An increase in pressure on an equilibrium system will shift the position of the equilibrium to the side having smaller volume and vice versa.
learn more:
Equilibrium brainly.com/question/10838453
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